
#1
Jul2108, 05:15 PM

P: 26

1. The problem statement, all variables and given/known data
The base of S is an elliptical region with boundary curve 9x^2 + 4y^2 = 36. Crosssections perpindicular to the xaxis are isosceles right triangles with hypotenuse in the base. Find the volume of the described solid. 2. Relevant equations V = {int} 1/2 b*h dy 3. The attempt at a solution I found that I would have to use the symmetry to solve this. The only things I have are x^2 + y^2 = 1/2 and y = sqrt(.5  x^2) Now i know I have to integrate an isosceles triangles area which is 1/2 b*h but I'm not sure what the base or the height will be. 



#2
Jul2108, 06:06 PM

Sci Advisor
HW Helper
Thanks
P: 26,167

Hi vigintitres!
9x^2 + 4y^2 = 36. The height you can work out because it's a rightangled isoceles triangle. 



#3
Aug408, 03:52 AM

P: 15

Find volume via method of crosssections.



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