greg997 said:A 400 Ohm resistor is connected in series with an inductor of reactance 300 Ohm and a capacitor C, and a 50 V voltage is applied to the circuit.
Find impedance.
Is it possible to calculate it? Am I missing something or I would need Xc or I to do that? Thank you for a hint.
greg997 said:Great thanks. One more question. I forgot to mention the Vs is at 0 degrees angle. Does it change anything?
Becouse Vs=sqrt(Vr^2+(Vl-Vc)^2), so I am thinking that in order to have Vs<0 angle , terms Vl-Vc must be zero. So that means the Xc=Xl= 200 Ohm. Am I right about that? Thank you
Impedance is a measure of the opposition to the flow of electric current in a circuit. It is represented by the symbol Z and is measured in ohms (Ω).
To calculate impedance, you need to know the values of resistance (R), inductance (L), and capacitance (C) in the circuit. The formula for calculating impedance is Z = √(R^2 + (XL-XC)^2), where XL is the inductive reactance and XC is the capacitive reactance.
The units of impedance are ohms (Ω), which represents the ratio of voltage to current in a circuit.
To calculate impedance for a circuit with a resistor, inductor, and voltage source, you can use the formula Z = R + jXL, where R is the resistance in ohms, XL is the inductive reactance in ohms, and j is the imaginary unit.
Using the formula Z = R + jXL, the impedance of this circuit would be 400 + j300 ohms. This means that the magnitude of the impedance is √(400^2 + 300^2) = 500 ohms, and the phase angle is arctan(300/400) = 37.5 degrees.