- #1
cps.13
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Hi,
I have the following question in my course work. What I do not understand is why it provides the relative density of natural gas?!
Calculate the equivalent choked flow of propane through a particular valve if the choked flow of natural gas through it is 10 litres s–1.
The relative density* of propane is 1.45 and that natural gas is 0.65. [*with reference to air]
I believe the equation I need to use is:
Qvf = Qvr * sqrt(1/d)
Where
Qvf = volumetric flow of the actual fluid (the propane)
Qvr = volumetric flow of the reference fluid (the natural gas) = 10l/s-1
d = relative density of the actual fluid = 1.45
So
Qvf = 10 * sqrt (1/1.45) = 8.304L/s-1
Am I going wrong somewhere?
Thanks
Homework Statement
I have the following question in my course work. What I do not understand is why it provides the relative density of natural gas?!
Calculate the equivalent choked flow of propane through a particular valve if the choked flow of natural gas through it is 10 litres s–1.
The relative density* of propane is 1.45 and that natural gas is 0.65. [*with reference to air]
Homework Equations
I believe the equation I need to use is:
Qvf = Qvr * sqrt(1/d)
Where
Qvf = volumetric flow of the actual fluid (the propane)
Qvr = volumetric flow of the reference fluid (the natural gas) = 10l/s-1
d = relative density of the actual fluid = 1.45
The Attempt at a Solution
So
Qvf = 10 * sqrt (1/1.45) = 8.304L/s-1
Am I going wrong somewhere?
Thanks