Calculating pump head required

[evoke1l1]

Homework Statement

I need to calculate the pump head required for a fluid transfer system.

The pump is located 3m above a storage vessel vented to atmosphere (1 bar) with a total pipe length of 5m to pump suction. The pump discharge is connected to a pressurised vessel at 2 bar absolute with an elevation of 15m and a total pipe length of 27m from pump discharge.

Homework Equations

Fluid Density 960 kg m^3

Head loss from friction on suction side: 0.266m
Minor head losses on suction side: 0.249m

Head loss from friction discharge side: 1.44m
Minor head losses on discharge side: 0.77m

The Attempt at a Solution

I've worked out the head required to overcome the pressurised vessel as:

p/ρg = 100000 / 960 × 9.81 = 10.62m

p = 100000 because this would be the gauge pressure in Pa.

To calculate the pump head required I have basically added the sum of height elevation (18m) plus the minor and frictional losses along with the head required to account for the 1 bar increased pressure of the pressurised vessel. This leaves me with an answer of 31.345m for pump head required (Hp).

Would this method be correct or do I need to re-evaluate my method?

 

[Chestermiller]

This looks OK to me.

 

[evoke1l1]

Thank you.