- #1
MiniOreo1998
- 18
- 0
Homework Statement
An electron is fired at 4.0 x 10^6 m/s horizontally between the parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C. The separation of the plates is 2.0 cm.
A) Find the acceleration of the electron between the plates.
B) Find the horizontal distance traveled by the electron when it hits the plate.
C) Find the velocity of the electron as it strikes the plate.
Starting to pick up steam and build some confidence. Still shaky on "proper notation" without flipping through pages, but I'm getting there (it's really just the beginning of each equation that makes me "iffy", I'm getting the hang of what order things should be in (which I'm starting to see will keep coming easier the more I work at it). Any suggestions are warmly invited!
Homework Equations
m a = ε q
Δdy = v1y Δt + 1/2 a Δt2
Δdx = v1x Δt
v2x = √ v1x + 2a Δdy
The Attempt at a Solution
A)
m a = ε q
a = ε q / m
a = (1.6 x 10-19) (4.0 x 102 / 9.11 x 10-31
a = 7.03 m/s2 [down]
B)
Δdy = v1y Δt + 1/2 a Δt2
0.2 = 0 Δt + 1/2 (7.03 x 1013)
Δt = (0.02) (2) / (7.03 x 1013)
Δt = 2.3 x 10-8
Δdx = v1 Δt
Δdx = (4.0 x 106) (2.3 x 10-8)
Δdx = 0.092 m
Δdx = 9.2 cm
C)
v2x = √ v1 + 2a Δdy
v2 = (4.0 x 106) + 2 (7.03 x 1013) (0.02)
v2 = 4.34 x 106 m/s2 [down]