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Derivative Using Dirac Delta Function
Let [tex]\theta[/tex](x) be the step function:
[tex]\theta[/tex](x) be equivalent to
1, if x > 0
0, if x [tex]\leq[/tex] 0
Show that [tex]\frac{d \theta }{dx}[/tex] = [tex]\delta[/tex](x)
In the previous portion I was able to prove
x [tex]\frac{d}{dx}[/tex] ([tex]\delta[/tex](x))= -[tex]\delta[/tex](x)
I thought the problem was a heavyside problem but upon closer inspection, I noticed that on the heavyside step function it is 1 when x [tex]\geq[/tex] 0.
So how do I resolve this? Is there a way to change it so that it looks like a heavyside function, because that makes the problem much more convenient.
Homework Statement
Let [tex]\theta[/tex](x) be the step function:
[tex]\theta[/tex](x) be equivalent to
1, if x > 0
0, if x [tex]\leq[/tex] 0
Show that [tex]\frac{d \theta }{dx}[/tex] = [tex]\delta[/tex](x)
Homework Equations
In the previous portion I was able to prove
x [tex]\frac{d}{dx}[/tex] ([tex]\delta[/tex](x))= -[tex]\delta[/tex](x)
The Attempt at a Solution
I thought the problem was a heavyside problem but upon closer inspection, I noticed that on the heavyside step function it is 1 when x [tex]\geq[/tex] 0.
So how do I resolve this? Is there a way to change it so that it looks like a heavyside function, because that makes the problem much more convenient.