Resistance of a Copper Wire with initial and final radius

In summary, the copper wire has a radius that increases as R(x)= aex+ b. Its initial radius is .45 mm and final radius is 9.67 mm and its horizontal length is 38 cm. The resistance of the wire is found using the Resistance formula for parallel circuits which is 1/Rtotal = 1/Rinitial + 1/Rfinal.
  • #1
jawhnay
37
0

Homework Statement



A Copper wire has a shape given by a radius that increases as R(x)= aex+ b. Its initial radius is .45 mm and final radius is 9.67 mm and its horizontal length is 38 cm. Find its resistance.

Homework Equations


R = pL/A where p = resistivity of copper
A = ∏r2
L = length of copper wire

resistivity of copper = 1.7 x 10-8

1/Rtotal = 1/Rinitial + 1/Rfinal

The Attempt at a Solution



My attempt at the solution was finding the resistance of the wire when the radius is initially at .45 mm and then finding the resistance of the wire at 9.67 mm using the formula R = pL/A. Then I tried adding those resistances together by using the Resistance formula for parallel circuits which is 1/Rtotal = 1/Rinitial + 1/Rfinal
 
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  • #2
Think of a small wire element of length [itex]dl[/itex] and find its resistance [itex]dR[/itex], then integrate over the length to find the total resistance.
 
  • #3
so you're saying R = pL/A ... dR = pdr/A what would my area be? Would it be A = ∏r2 or A = 2∏rL How exactly do I go about doing this?
 
  • #4
Can anyone else offer any insight on how to do this problem?
 
  • #5
So you're given:
r(x) = a*e^x + b
r(0 m) = 0.45e-3 m
r(38e-2 m) = 9.67e-3 m

A(x) = π*r(x)^2

You could imagine summing up the resistances of a bunch of thin slices of wire with width dx as a heuristic to help you set up the integral:
[tex]
R(x_e) = \int_0^{x_e} \frac{\rho}{A(x)} \mathrm{d}x
[/tex]
 
  • #6
where are you getting r(0 m) = 0.45e-3 m and r(38e-2 m) = 9.67e-3 m ?
 
  • #7
Let x = 0 cm and x = 38 cm represent the endpoints with the small and large radius, respectively. You're then given the values that r(x) should take at these endpoints.
 
  • #8
How do you know that r(0) = .45 x 10-3 and r(.38) = 9.67 x 10-3 ? I'm kind of confused... Can anyone make this clearer for me?
 
  • #9
Imagine putting a coordinate axis down the length of the wire. You could call this the x-coordinate axis and x would represent a specific position along the length of the wire.

You know the length of the wire is 38 cm and the radii of the thin and thick ends are 0.45 mm and 9.67 mm, respectively. You also know how the radius of the wire changes from one end to the other.

If r(x) is the radius at position x, you could let x = 0 represent the thin end of the wire and x = 0.38 could then be the thick end (it's usually good practice to convert everything to SI base units, meter [m] for length).

Does that help?
 

Related to Resistance of a Copper Wire with initial and final radius

1. What factors affect the resistance of a copper wire?

The resistance of a copper wire is affected by its length, cross-sectional area, and temperature. A longer wire will have higher resistance, while a larger cross-sectional area and higher temperature will decrease the resistance.

2. How does the initial and final radius of a copper wire affect its resistance?

The initial and final radius of a copper wire are inversely proportional to its resistance. This means that as the radius increases, the resistance decreases, and vice versa.

3. How do you calculate the resistance of a copper wire with initial and final radius?

The resistance of a copper wire can be calculated using the formula R = (ρ * L) / A, where R is the resistance in ohms, ρ is the resistivity of copper, L is the length of the wire, and A is the cross-sectional area. The initial and final radius can be used to calculate the cross-sectional area.

4. Why is copper a good material for wires?

Copper is a good material for wires because it has a low resistivity, meaning it allows electricity to flow easily. It is also durable and malleable, making it easy to shape into wires.

5. How does the resistance of a copper wire change over time?

The resistance of a copper wire can change over time due to factors such as corrosion, which can increase resistance, or changes in temperature, which can decrease resistance. It is important to regularly check and maintain copper wires to ensure their proper functioning.

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