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Find an angle between 0 and 360 degrees for which the ratio of sin to cos is -3. I know this seems to be an easy question, but I am stuck. I appreciate for those helping me.
snipez90 said:Ok... that's not quite the response I was expecting. Do you understand the kind of analysis used to solve this problem? If your calculator doesn't have a degree mode, you could use the conversion factor [tex]\frac{\pi}{180\deg} = 1[/tex].
Solving for Sin/Cos Ratio of -3 in [0,360] Degrees means finding the values of sin(x) and cos(x) when the ratio of sin(x)/cos(x) is equal to -3, within the range of 0 to 360 degrees.
Solving for Sin/Cos Ratio of -3 in [0,360] Degrees is important for understanding the behavior and patterns of trigonometric functions, as well as for solving real-world problems that involve angles and ratios.
The method for solving Sin/Cos Ratio of -3 in [0,360] Degrees is to use the unit circle and trigonometric identities to find the values of sin(x) and cos(x) that satisfy the given ratio.
Yes, there is a specific formula for solving Sin/Cos Ratio of -3 in [0,360] Degrees. It is sin(x)/cos(x) = -3, where x is an angle within the range of 0 to 360 degrees.
Some common mistakes to avoid when solving for Sin/Cos Ratio of -3 in [0,360] Degrees include forgetting to use the correct units (radians or degrees), not considering all possible solutions, and making calculation errors with trigonometric functions.