- #1
emrys
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Homework Statement
(x2+3x+3)1/3 + (2x2+3x+2)1/3 = 6x2+12x+8
2.Relevant equations
The Attempt at a Solution
(x2+3x+3)1/3 -1 +(2x2+3x+2)1/3 -1 = 6x2+12x+6
(x2+3x+2)/((((x2+3x+3)1/3)2 + (x2+3x+3)1/3 +1) + (2x2 +3x+1)/((((2x2+3x+2)1/3)2)+(2x2+3x+2)1/3 +1) -6(x+1)2=0
then
x=-1
or
(x+2)/((((2x2+3x+2)1/3)2)+(2x2+3x+2)1/3 +1)-6(x+1)=0 (*)
now there is 1 root left it is also -1 but no common factor in (*)
sorry i am not good at english