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mnoir
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Homework Statement
An electron with kinetic energy 5 eV (8.01E-19 J) passes through a 3 eV (4.806E-19 J) potential barrier. There are certain widths for this potential barrier in which the transmission probability will equal one hundred percent and the reflection probability will equal zero. Find the smallest non-trivial width in which this occurs.
Homework Equations
R = [i(q2-k2)sin(2qa)exp(-2ika)] / [2kqcos(2qa)-i(k2+q2)sin(2qa)]
T = [2kqexp(-2ika)] / [2kqcos(2qa)-i(k2+q2)sin(2qa)]
k = sqrt(2mE) / hbar
q = sqrt[2m(E-V0)] / hbar
width = 2a
i is imaginary
q = sqrt[2m(E-V0)] / hbar
k = sqrt(2mE) / hbar
m=9.1094E-31 kg
hbar=1.0546E-34 J*s
The Attempt at a Solution
k=1.15E10
q=7.24E9
From here I think you would set T=1 and R=0 and solve for a. I'm not sure if this method is correct, but if so, after plugging in k and q, how do I solve for a if it's in cos, sin, and exp?
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