Voltage drop across voltage divider

In summary, a voltage divider with two resistors R1 and R2 produces a voltage VB that is always equal to the base emitter voltage = 0.7v.
  • #1
Frankrules
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Homework Statement


A voltage divider with two resistors R1 and R2 is given. The output is connected to a transistor so VB is always equal to the base emitter voltage=0.7v.

Homework Equations



How can i explain physicaly (wath happens to the electron flow and such) why when R1 is verry high, VB is lower then 0.7V. I know all the math and theory behind that, but i want to be able to understand that on the verry basic scale. I mean like when you explain what heat is and you say that heat is the friction of the atoms caused by let's say a passing electron flow.

The Attempt at a Solution

 
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  • #2
Frankrules said:
I know all the math and theory

good question. not obvious how tor reconcile physical effects [observations, measurements] with theory. Einstein was GREAT at that; he had visionary physical insights.

You can think of the current flow in two parts.

First, electrons bump along, one against the other in a continuous line. Individually they move rather slowly. See drift current in resistors and diffusion current for semiconductors.
https://en.wikipedia.org/wiki/Diffusion_current

You can think of conduction electrons in a circuit bumping along akin to cars entering and leaving highway entrances and exits: when one is pushed free by an electrical potential, an emf, others are pushed also very quickly but less than the speed of light. When one electron enters a resistor, another exits almost immediately. They cannot build up in a resistor.

q=it and i = E/R so q = Et/R so what happens when voltage E is increased...more charge [q] flows...electrons get pushed along faster! This assumes R is constant and that's an approximation since resistances can get hot...like on an electric stove top. What happens when more times passes at a fixed voltage...same thing, if your source is a battery, chemical changes deplete the battery.

Conductors have loosely bound outer electrons, resistors have more tightly bound electrons, and in insulators electrons are REALLY tightly connected to their individual atoms. High resistances have conduction electrons more tightly bound than low resistances.
Try here for additional detail: https://en.wikipedia.org/wiki/Valence_and_conduction_bands#Electrical_conductivity
 
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  • #3
It's sometimes worth taking things to extremes... What happens if R1 is infinite eg removed from the circuit?
 
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  • #4
alw34 said:
good question. not obvious how tor reconcile physical effects [observations, measurements] with theory. Einstein was GREAT at that; he had visionary physical insights.

You can think of the current flow in two parts.

First, electrons bump along, one against the other in a continuous line. Individually they move rather slowly. See drift current in resistors and diffusion current for semiconductors.
https://en.wikipedia.org/wiki/Diffusion_current

You can think of conduction electrons in a circuit bumping along akin to cars entering and leaving highway entrances and exits: when one is pushed free by an electrical potential, an emf, others are pushed also very quickly but less than the speed of light. When one electron enters a resistor, another exits almost immediately. They cannot build up in a resistor.

q=it and i = E/R so q = Et/R so what happens when voltage E is increased...more charge [q] flows...electrons get pushed along faster! This assumes R is constant and that's an approximation since resistances can get hot...like on an electric stove top. What happens when more times passes at a fixed voltage...same thing, if your source is a battery, chemical changes deplete the battery.

Conductors have loosely bound outer electrons, resistors have more tightly bound electrons, and in insulators electrons are REALLY tightly connected to their individual atoms. High resistances have conduction electrons more tightly bound than low resistances.
Try here for additional detail: https://en.wikipedia.org/wiki/Valence_and_conduction_bands#Electrical_conductivity
Oops, sorry i write that twice, but i am new here and clicked the wrong thing the first time:-D. Thank you for youre answer, it really helped me out :-)
 
  • #5
CWatters said:
It's sometimes worth taking things to extremes... What happens if R1 is infinite eg removed from the circuit?
Good question, CWatters! Apperantly all resistors are in nature still conduct. In order to conduct, they must have loosely held electrons. As a resistance grows, it gets harder and harder for these electrons to break, until atlast, in nonconductive materials there are no free charges. Current just can't flow through such material couse in order to flow, there must be free charges.
At first, all voltage drops across R1, then you connect R2 and the voltage drops to 0,7v after R1. If R1 resistance is increased, VB falls beneath 0,7v and the transistor is in cut off mode. But what really is voltage drop?- in resistors the electron's velocity is reduced. That electron applies a repulsion force on the one behind him and a chain reaction occurs. If the current through R2 is I2, then that current applies the same repulsion force to the base current and maybe that slows it enough so that it can't leave the pn junction.. But do i really need to go that deeply with the physics? (i study for engineer)
 
  • #6
alw34 said:
q=it and i = E/R so q = Et/R so what happens when voltage E is increased...more charge [q] flows...electrons get pushed along faster!

Rereading this, I realize I should have also mentioned that with more energy, more emf, more electrons are ripped free from their atom, although it is mentioned in the second reference I posted:
"As such, the electrical conductivity of a solid depends on its capability to flow electrons from valence band to conduction band."
See also the comments there about " In solids, the ability of electrons to act as charge carriers depends on availability of vacant electronic states..."

So when the basic math of electrical circuits was formulated, mostly likely people did NOT understand the underlying mechanisms, especially in semiconductors which not yet been invented. That's common in science where progress is made over time as theory, discoveries and scientific apparatus advances.

You might also think about why resistors get hot.
CWatters said:
It's sometimes worth taking things to extremes

That's a good tip, especially when you are not sure about the incremental direction a change might make. Assuming infinite resistance [open circuit] or zero resistance [short circuit] usually points you in the right direction...similar for mechanical situations, even relativity.
 
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  • #7
alw34 said:
Rereading this, I realize I should have also mentioned that with more energy, more emf, more electrons are ripped free from their atom, although it is mentioned in the second reference I posted:
"As such, the electrical conductivity of a solid depends on its capability to flow electrons from valence band to conduction band."
See also the comments there about " In solids, the ability of electrons to act as charge carriers depends on availability of vacant electronic states..."

So when the basic math of electrical circuits was formulated, mostly likely people did NOT understand the underlying mechanisms, especially in semiconductors which not yet been invented. That's common in science where progress is made over time as theory, discoveries and scientific apparatus advances.

You might also think about why resistors get hot.

That's a good tip, especially when you are not sure about the incremental direction a change might make. Assuming infinite resistance [open circuit] or zero resistance [short circuit] usually points you in the right direction...similar for mechanical situations, even relativity.
Oooh, i think i get it now:-D. Not so long ago i searched the internet for explanation on how charhed particles get their charge.. only to find later that this wasnt yet explained by science. We live in a such era, that we use basic laws (Ohms law for exam) that were invented long ago, and something in them we understand both theoreticaly and physicaly, but something we still don't have answer for, but we continue using it, couse we know that the law tells us its correct.
 
  • #8
Frankrules said:
Not so long ago i searched the internet for explanation on how charhed particles get their charge.. only to find later that this wasnt yet explained by science.

If you read about the Standard Model of Particle Physics, which contains our accumulated knowledge of all sub atomic particles you might even be discouraged: Despite all the great accumulated scientific knowledge that has been amassed, despite our ability to model and predict so many things, nobody knows just what the fundamental particles 'really are'. Some think that's not the role of physics; I think it is, and hopefully someday we'll understand 'why' the electron, for example, has the charge and mass we measure.
 
  • #9
Frankrules said:
At first, all voltage drops across R1, then you connect R2 and the voltage drops to 0,7v after R1.

Perhaps you should post a circuit because I don't think this is correct.
If R1 resistance is increased, VB falls beneath 0,7v and the transistor is in cut off mode.

That is correct.
But what really is voltage drop?- in resistors the electron's velocity is reduced. That electron applies a repulsion force on the one behind him and a chain reaction occurs. If the current through R2 is I2, then that current applies the same repulsion force to the base current and maybe that slows it enough so that it can't leave the pn junction.. But do i really need to go that deeply with the physics? (i study for engineer)

A bipolar transistor is a device that manipulates current - so in general it is best to think about the base current rather than the base voltage.
 

1. What is a voltage divider?

A voltage divider is an electrical circuit that divides a voltage into smaller parts using resistors. It is commonly used in electronic devices to provide a specific output voltage.

2. How does a voltage divider work?

A voltage divider works by using two or more resistors in series to create a voltage drop. The voltage across each resistor is proportional to its resistance, and the total voltage drop across the divider is equal to the supply voltage.

3. What is the formula for calculating voltage drop across a voltage divider?

The formula for calculating voltage drop across a voltage divider is Vout = (R2 / (R1 + R2)) * Vin, where Vout is the output voltage, R1 and R2 are the resistances of the two resistors, and Vin is the input voltage.

4. What factors affect the voltage drop in a voltage divider?

The voltage drop in a voltage divider is affected by the values of the resistors used, the input voltage, and the load connected to the output. Higher resistance values will result in a larger voltage drop.

5. How can I reduce voltage drop in a voltage divider?

To reduce voltage drop in a voltage divider, you can use resistors with lower resistance values, increase the input voltage, or decrease the load connected to the output. However, this may also affect the output voltage, so it is important to carefully select the resistor values and input voltage to achieve the desired output.

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