Recent content by 1man

thank you

A baseball is thrown directly upward at time t=0 and is caught again at time t=5\;\rm s. Assume that air resistance is so small that it can be ignored and that the zero point of gravitational potential energy is located at the position at which the ball leaves the thrower's hand. I need to...

im looking for the tension and the tension wouldn't be 0 because if it were the bucket would be falling

Homework Statement A 6-kg bucket of water is being pulled straight up by a string at a constant speed. What is the tension in the rope? about 42 N about 60 N about 78 N 0 N because the bucket has no acceleration. Homework Equations \SigmaF=ma ma=T-mg T=ma+mg The...

or (2A)x(3B)

they are and i already know Rz=Az+Bz Ry=Ay+By Rz=Az+Bz but I am not sure how to do (2A)x(3C)

i'm reviewing for a test and I can't remember how to do the cross product of (2A)x(3B) or how to find the angle theta when given components. or dot product: 2A . 3B

For the motion diagram given , sketch the shape of the corresponding motion graphs in Parts A to D. Use the indicated coordinate system. One unit of time elapses between consecutive dots in the motion diagram. I've already constructed an x vs t and y vs t graph please help me with these...

Physics please help with Motion of Two Rockets? Two toy rockets are traveling in the same direction (taken to be the x axis). A diagram is shown of a time-exposure image where a stroboscope has illuminated the rockets at the uniform time intervals indicated...

ty so much for your help

i get -13, 6, -11, if my calculations are correct. do i need to find the magnitude of this? sqrt of 326... hen divide by this amount for each. Do I also need to change the +/- signs to make it perpendicular

Given two vectors \vec{A} = - 2.00 \hat{ i } + 3.00 \hat{ j } + 4.00 \hat{k} and \vec{B} = 3.00 \hat{ i } + 1.00 \hat{ j } - 3.00 \hat{k}. Obtain a unit vector perpendicular to these two vectors. Express your answer as a unit vector N_unit in the form N_x, N_y, N_z where the x, y, and z...

K_2-K_1 where k=1/2*m*v^2, thank you, it would be .58v not .42, in the equation -.2gs = (1/2)mvf^2 - (1/2)mvi^2 where the m cancel

On an essentially frictionless, horizontal ice rink, a skater moving at 6.0 m/s encounters a rough patch that reduces her speed by 42 \% due to a friction force that is 20 \% of her weight. Use the work-energy theorem to find the length of this rough patch. i do: [.42 * (.5) * (6)^2]/ [.2...

thank you so much Spinnor!