I somewhat figured out that
They are apparently. I'm used to solving the inclined versions of these. I wonder why I'm having this much trouble on a horizontal one
Ok , so this gave me an idea
∑Fx = 0
F = 40 N
F - Ff + W ( a / g ) = 0
So if I compute again
40 - Ff + 100 ( 8m/s2 / 9.806)
I would get a Ff of 121.5827 N
divide that by 100 and I get a coefficient of 1.22
Seems pretty large for a coefficient of friction
The inertia naturally resists the motion so it's negative, frictional force too. Weight is multiplied by the cosine of 90 so it's technically zero. Force appears to be going to the right so it's positive. I'm still having trouble why it's a negative value when computed
Homework Statement
Ignore B & C for now
The block in the figure reaches a velocity of 40 m/sec in 100 m, starting from rest. Compute the coefficient of kinetic friction between the block and the ground.
W = 100N
F = 40 N
2. Homework Equations
∑Fy = 0 so Normal Force = Weight
∑Fx =...
Homework Statement
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http://www.electronics-tutorials.ws/combination/comb_7.html
http://www.allaboutcircuits.com/textbook/digital/chpt-9/full-adder/
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Homework Statement
We are asked to make a subtractor circuit which has a 2 bit, 2 input data.
Homework Equations
A1A0
_
B1B0
_________________________________The Attempt at a Solution
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