Recent content by Arooj

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    Possible to find the direction of magnetic force if angle isn't 90?

    Homework Statement Find the force on 7.0 cm of conductor bearing a current of 6A if it lies perpendicular to a magnetic field of intensity 1.2 T and the wire makes an angle of 60° with the magnetic field? Homework Equations F = IlB sin θ The Attempt at a Solution The magnetic force...
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    Solving Final Temp of Ice & Water Mixture

    To get 28.08 I did Qw=-Qx (0.5 *4.186 * 10^3 *(Tf-100)) = -((0.1 *4.186 * 10^3 *(Tf-0)) + (0.1 * 3.33 * 10^5)) 2093Tf - 209300 = -418.6Tf - 33300 2511.6Tf = 176000 Tf = 70.07 C I think I have it, I might have made some original mistake in calculation.
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    Solving Final Temp of Ice & Water Mixture

    Thanks for the help. Not including the heat of vaporization, I got 28.08 C. I also did have a mistake in calculating the energy of the piece of ice where I put it the mass of the water instead. Is 28.08 a reasonable answer, or should it be closer to 100 C because the more massive object would...
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    Solving Final Temp of Ice & Water Mixture

    Homework Statement A 100g piece of ice at 0.0°C is dropped into 500g of water at 100°C. What is the final temperature of mixture. Homework Equations Q=mL (latent heat) Q=mcΔt Qw=-Qx (energy absorbed by water is equal but opposite to that of substance inserted into water) specific...
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    Tricky Torque Problem: Solving for Tension and Understanding Beam Forces

    And compression would thus be opposite to the force exerted by the wall, for a net force of zero?
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    Tricky Torque Problem: Solving for Tension and Understanding Beam Forces

    ah, so there is no F, meaning it would just be 980 = sin 37 T, where T is the tension. net force = zero, forces left = forces right, forces up = forces down, clockwise torques = counterclockwise torques, x and y components of force may separately be set to 0. And T cos 37 would give the force...
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    Tricky Torque Problem: Solving for Tension and Understanding Beam Forces

    Homework Statement The writing was just my reasoning, which I don't think is right. Assume the beam is massless. Homework Equations T = Fd sin θ F = mg net force must be zero. net torque must be zero. The Attempt at a Solution d * 1/2F + 980 = d * (sin 37) T 1/2 F + 980 = (sin 37) T I don't...
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    Difficult Centripetal Motion Problem

    Homework Statement Tarzan swings from a vine 20 m long which makes an angle of 30° with the vertical. If he pushes off with a speed of 2 m/s, what is the tension in the vine at the lowest point of the swing? Tarzan has a mass of 80 kg.Homework Equations centripetal accelaration force = F m =...
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    How Does Height Above Earth Affect Satellite Weight?

    Homework Statement What is the weight of a 200 kg satellite 12.8 * 10^6 m above the surface of the Earth. Homework Equations F = mg The Attempt at a Solution F=200 (9.81) F = 1962 N I thought this was a basic weight problem, but I was confused on whether the height above the...
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    Conservation of Momentum problem

    Thanks, I did so and found the final velocity to be 15.66 m/s. I'm confused on how to find the correct angle to use though for the direction is it the tan x comp over the y comp or the other way around? And how would you know which one it is?
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    Conservation of Momentum problem

    Homework Statement A 1500-kg car is traveling north at 25 m/s when it strikes a 2000-kg car traveling east at 20 m/s. The cars stick together after the collision. What is the final velocity of the two cars? Homework Equations m1v1 + m2v2 = (m1 + m2)vf The Attempt at a Solution...
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    A bullet strikes a wooden block

    So the length of the string doesn't matter?
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    A bullet strikes a wooden block

    Homework Statement A 25 g bullet is fired at 150 m/s into a 2.0 kg block of wood hanging from a string 3.0 m long. The bullet becomes embedded in the block. To what height do the bullet and block swing? Homework Equations m1v1 = (m1+m2)vf 1/2 mv^2 = mgh The Attempt at a Solution...
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    What are the final velocities of two balls after an elastic head-on collision?

    Ah I see what I did wrong, v2 = 4.4 , and v1 = -13.6, substituting them into the conservation of momentum equation yields 14 = 14.
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    What are the final velocities of two balls after an elastic head-on collision?

    vf1 = ((m1)(v1) + m2((2*v2) - v1)) / m1 + m2 vf1 = (16 + 3(-20 - 8))/5 vf1 = -13.6 m/s vf2 = v1 + vf1 - v2 vf2 = 8 + -13.6 - 10 vf2= -15.6 m/s I'm assuming my problem is from setting the values of the speeds in the opposite direction to negative, but I thought this must be done?
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