Recent content by bharath423

but previously i was not asking to explain the impedance function to for capacitor.. anyway thank u for that link... i was asking you to take two port RC network just like low pass filter..and asked for the transfer function i.e, input voltage(to RC network) to output voltage(at capacitor)...

thank you naty...but i came to know that transfer function is just defined like that to have zero intial conditions...so there isn't any particular reason to define it so,but they defined it only to get the ease of calculations..i think so..

can u explain me with equations... i mean..take a simple RC circuit...with measuring,output voltage at the capacitor...say it has a initial voltage.. i had done it but i was not able to resolve the equation for input to output form..

why in a transfer function it is written by considering the initial condition to zero.. because if we individual write the integro-differential equation and apply Laplace transform to them and obtain a output/input relation,it definitely contains the initial condition terms in it also.. so...

so divergence is calculated at a particular point only...then in case we calculate for a surface then we get all the sources and sinks which is nothing but the total charge...and this is what gauss law says ..im correct??

so the divergence at a point shows the sink or source at a given point...so if at r=0 we are able to calculate the divergence then it would be equal to guass law result..is that what you are saying? if that is so, then divergence for every field except at the source of the field, every where it...

The D field due to a point charge(Q) has a divergence zero D = (Q/(4*pi*r2)) ar (ar --- unit vector) if we calculate the divergence we get zero. but guass law says that the divergence is a finite value not zero because a charge is present in there...

yes..thank u...

Homework Statement The net charge in a current-carrying wire is zero.Then,why does a magnetic field exert a force on it? Homework Equations dF=I*dl x B The Attempt at a Solution if we take a small portion of wire the net charge is zero,so if i take the frame of electrons that is I am moving...

u just need to know the potential difference between the plate...no need of distance..and charge is already given

intrinsic carrier concentration=(2.33 * (10)^43) * ( ..(.. (Mn*Mp) / (M^2).. ) ^(3/2).. ) * (T ^3) * (e ^ (-Eg/kT) ) Mn=effective mass of electron Mp=effective mass of hole M=mass of electron T=temperature in kelvin Eg=energy gap at particular T k=boltzman constant e=mathametical constant e. i...

yes collinsmark you are right thank u for correcting me if A was allowed to move, B and C stay fixed in place...i missed that point so now we can find the resultant forces on each charge,as we know direction of movement we can also apply conservation of moment,and the equation Cracking has...

when we insert a conductor in between due to field -ve charge comes on one side and +ve charge on the other and since its a conductor Electric field inside is zero so charge comes on to surface,so its just like two new capacitors with distance between palates is d/3 each.. potential drops as...

Actually if u find potential energy of A due to B and C.. that is what converts into kinetic energy so 1/2*mass*(velocity of A)*(velocity of A)=Potential energy of A we just found (this hold only in this case as we took potential at infinity as zero and the initial velocity is zero...

k yes the charge should remain the same,its not the charge flowing out..but the force changing because now we have a relative permittivity in the force equation constant!