Recent content by chickens

Homework Statement L[cos(at)cosh(at)] = ? Homework Equations L[cos(at)] = s/(s^2 + w^2) The Attempt at a Solution I'm able to get the solution given that is (s^3)/(s^4 + 4a^4) The question requested to use first shift property. So I used cosh(at) = 1/2[e^at + e^(-at)]...

simplify f(x)g(x) using simple algebra properties first then only apply some log rule like log ab = log a + log b i'm not too sure if d/dx log ab = d/dx log a + d/dx log b, but you may give it a try

sin^2 4@ == (sin 4@)^2 then if u do like normal differentiation, u get 8sin4@cos4@ and with the trigo identity, u will get 4 sin8@ thus, that result would approaches 0 for @ --> 0 ps: sorry, don't know how to use the mathematical notation thingy

hmm tried doing the q...do u have the answer to this q...? I got 4.8V but i didnt use any current thingy, just all on current divider rule

didnt know i can't do that, really sorry, next time will post a guided solution rather than a complete one

(x'y'+z')' +z +xy+ wz = use de morgan's law, (x.y)' = x' + y' | (x+y)' = x'.y' = take out the common factor, anything +1 = 1 = z.1 + xy = z + xy hope this helps

anyway...mind reedit the latex thing... can't seem to get them =_=

yup...sorry... the contour suppose to go from (1,1) to (0,0) thanks for the mistake pointed out :)

In tutorial classes, they gave a semicircle and that was quite easy to get it... but this geometrical shape triangle... is my first time trying it, and i got so say... its cracking my head (i know its simple stuff...but i really don't get where went wrong)

i'm not sure about the ds part as usually there is this table i would refer to, and it says ds = dxdy z_hat but ... I've also tried doing using it, i won't get the same answer. If need to integrate over a circle, transform the vector to cylindrical type and use cylindrical variables r phi z...

sorry... that ds suppose to have z_hat with it

Hi guys... I'm stuck in this question. Its not a homework nor coursework, just practice. The answer for both is the same, that is -1 ...I'm able to get (a) but (b) ... still wondering what went wrong. Please enlighten me. Thanks in advance.

ahhh, lol a set up q :P thanks for the explanation... then what about the second solution? it seems simple but doesn't seem that right lol

yes that equation is for the condition to get constructive interference...but for the delta m...i know it can't have the same m, but can't the first point of overlap is when delta m = 2 or 3 or so on?

no one could help to explain ? :(