Recent content by Chip

It seems that the latest data out of CERN suggest a mass of the Higgs Boson that is smack in the middle of what would be suggested by parallel universes/string theory and SuSy. Do you think Edward Whitten, Savas Dimopoulos, and probably others could get together in a room to unify these two...

Well, maybe I just need to work side my side with someone on this. I just can't seem to get to the answer..

The following code compares my result to the known correct result. Can anyone find where my error is? If you run the octave code you will see that my answer has positive concavity whereas the correct one has negative concavity...I've checked this so many times and can't find my error. I wanted...

No. The situation still reduces to the principle of the conservation of linear momentum, and you will still get a kick. The forces you speak of will cancel, but you will still have the impulse at the back of the gun, ie. in your case at the locations of the L curvature. If you want a gun...

Homework Statement Rectangular barrier of width a and height V0 with an E < V0. What is the transmission ratio, T? Homework Equations T = C*C/A*A What am I missing in my attempted solution (variable name = TChip), which is different from the known solution (variable name = TSoln)? The Attempt...

OK, I believe I figured this all out. I had inserted for the position operator, x - xNot, which means I shifted the POTENTIAL along with the parameter of the eigenfunction, and of course annihilated to zero; if you shift everything over you get the same thing! I, instead, was NOT supposed to...

Maybe a picture will help. http://chipreuben.com/annihilation-of-shifted-Gaussian.jpg I get zero, both with the shifted and the non-shifted. Can anyone tell why the nonshifted should yield the ground state eigenfunction multiplied up by a constant? It seems the answer has to do with expanding...

Now that I have corrected my errors, this is precisely what I am getting. The question is: why then is Alan Adams getting something else?? Please watch the portion of the video I referenced above and let me know what your think! Thanks in advance!

Sorry, yes, I need to learn LaTex, but in this case I am now getting zero...just as you seemed to be stating above...whether or not I shift...so it would be great if you could check out this video starting at 6:15 into the video through about 8:00 (I know it is a little pesky but keep clicking a...

Thank you for your response. actually in the exponential of the eigenfunction you actually should have 2* hbar in the numerator and m * omega in the denominator--so you have the reciprocal of the coefficient...as a check the exponential should be dimensionless, hence the xNot in the...

It does as you say for the unshifted phi-ground, but for the shifted one it yields the x*phi-ground coefficient when I evaluate as you suggest, ie. on the left side, to yield this term on the ride side of the equation. Either I have an error or am misunderstanding something. The annihilation...

You could start with a primer such as this one: http://www.sumanasinc.com/webcontent/animations/content/highthroughput.html

Oh, I want to mention one more thing in reference to the fact that you are in Turkey. I've researched quite a few pharmacologic studies in Turkey, and had a few conversations with a brilliant medical researcher I know. There has been noted a phenomenon in Turkey of a requirement of increased...

My exposure to this area comes from reading papers, ie. mostly reviews. My hunch is that if you try to study the microbiome in any detail you will encounter precipitously diminishing returns in terms of accuracy, usefulness, reliability, etc. As with anything else extremely complex, you face an...

Sorry, yes, I was in error...I rechecked the work and did get one term only, and it was proportional to x (actually x - xNot in this case), so it was actually: C1 (x-xNot) * phi-ground(x-xNot), where C1 = some other constant * (1/xNot -1)...but according to that video the answer is just C1...