Thanks mrjeffy321, pure water did turn out to be the right answer. I see what I did wrong now (I definitely have a habit of making things harder than they should be, haha)..thanks again for your help
It's driving me crazy that I can't figure this out. I've read the section in the book like 5 times and its not helping at all...argh.. Here it is:
In which of the following aqueous solutions would you expect AgCl to have the highest solubility?
pure water
0.020 M BaCl2
0.015 NaCl
0.020...
ok if i think of the orbit of the Earth around the sun
the radius between the Earth and sun is 1.496 X10^11 m
the surface area is 4pi(r^2) which comes out to 2.81 X10^23
then if I use the equation you gave me above 1350 X (2.81 X 10^23) = 3.8 X 10^26, THE RIGHT ANSWER!
thank you both so much...
the area over which the energy has spread out is over the Earth, right? surface area = 4(pi)r^2 = 5.11 X 10^8..but only part of the energy is hitting the earth, the rest is going out into the space, right?? I am lost
No, I dont...This book is confusing, there isn't anything about power in the chapter in relation to the intensity, that's why I was looking through old chapters to see if there is a formula or something that could convert intensity into power outage. Just looking at the units, the intensity is...
Hi, if someone could help me figure this out I'd really appreciate it.
Estimate the average power output of the Sun, given that about 1350 W/m^2 reaches the upper atmosphere of the Earth.
I know the answer is 3.8 X 10^26 W but I don't know how to get there. I've tried different equations...
Show that the power loss in transmission lines, PL, is given by PL = (PT)^2 X R/(V^2), where PT is the power trasmitted to the user, V is the delivered voltage, and R is the resistance to the power lines.
I don't even know where to start. I am so confused by this chapter, I don't know what...
K(a) for HX is 7.5 x 10^-12. What is the pH of a 0.15-M aqueous solution of NaX?
a. 7.87
b. 1.85
c. 5.97
d. 8.03
e. 12.15
HX --> H+ + X-
I found H+ concentration, which is 1.06 X 10-6, then found pH of this, and it is 5.97. I wasn't sure where to go from here so I guessed...
A small immersion heater can be used in a car to heat a cup of water for coffee or tea. If the heater can heat 120 mL of water from 25 C to 95 C in 8 minutes, a) approximately how much current does it draw from the car's 12-V battery, and b) what is its reistance? Assume the manufacturer's claim...
Hi, yes the answers are exactly as my WEBCT has them.
I understand where I was messing up on the moles, but now I have an answer of 113!
Relate the change
.3945 mol N2O4/L (2 mol NO2/1 mol N2O4) = .789 mol NO2/L
0+.789 = .789 for the NO2 so [.789]^2/[.0055] = 113
is that the answer that...
I feel like I know what I'm doing but I'm not getting an answer that is offered. Heres the question:
Dinitrogentetraoxide partially decomposes according to the following equilibrium:
N2O4 (g) ---> 2NO2 (g) (an arrow going other way too)
A 1.00-L flask is charged with .400 mol...
Speed of waves in a cup of coffee that spills over, help please!
"When you walk with a cup of coffee (diameter 9 cm) at just the right pace of about 1 step per second, the coffee builds up its "sloshing" until eventually, after a few steps, it starts to spill over the top. What is the speed of...
I am having trouble understanding this..
If reactions are spontaneous when they create more entropy (disorder), why is it that most spontaneous reactions are exothermic? Such as an exothermic reaction like A + B ---> AB + Energy, AB then has lower energy than the reactants, which also means...
Yea, there are two slots in my Webassign, I am looking for the force first and then absolute pressure. Sorry I should have clarified that.
you got 81619? I keep getting 81536..am I missing a number??
I don't understand WHY my Webassign says I have this wrong. Here is the problem:
" What are the total force and the absolute pressure on the bottom of a swimming pool 2.6 m by 1.6 m whose uniform depth is 2.0 m?"
My book says the force = density X Area X depth below the surface X g
so f...