Recent content by Crazy Gnome

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    How to Apply L'Hopital's Rule to Probability Equations?

    The problem statement Using the Equation P(\theta)= P1[ \frac{sin(Nkdsin(\theta)/2)}{sin(kdsin(\theta)/2)} ]2 show that the probability at sin(\theta)=j\frac{\lambda}{d}, where j is an integer, is P(\theta=sin-1(j\lambda/d))=N2P1 Hit: find...
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    Solve Ampere's Law Problem for Uniform Current Density

    Homework Statement A conducting slab of thickness a is bounded by the planes z= \pma/2 and carries a uniform current density J=J (y hat) Use the integral form of Ampere's law to to find magnetic field everywhere 2. Relevant equations Integral for of Amperes law: Integral (B \bullet ds) =...
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    Calculate Magnetic Induction in Cylindrical Hole w/ Uniform Current

    Question: An infinite cylindrical wire with radius 2R caries a uniform current density J=Jz, except in an infinite cylindrical hole parallel to the wires axis. The hole has a radius of R and is tangent to the exterior of the wire. Calculate the magnetic induction B everywhere inside the hole...
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    Solve Maclaurin Series for f(x)= 1/(1+x+X2)

    Homework Statement Find the Maclaurin series for f(x)= 1/ (1+x+X2) Homework Equations The Attempt at a Solution I think the book says I can just divide 1 by the Maclaurin series of (1+x+X2). And when i do this the original function is the answer (which makes sense). But when...
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    Electric Potential: Find Potential Everywhere with q and -q on Z-Axis

    1. Homework Statement Two point charges q and -q are located on the z axis at (x,y,z) = (0,0,a) and (0,0,-a) respectively. Find the potential \phi everywhere 3. The Attempt at a Solution I know all the equations and such, I just don't know how to integrate it. I am guessing that...
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    Electric Potential: Find Potential Everywhere from Two Point Charges

    Homework Statement Two point charges q and -q are located on the z axis at (x,y,z) = (0,0,a) and (0,0,-a) respectively. Find the potential \phi everwhere The Attempt at a Solution I know all the equations and such, I just don't know how to integrate it. I am guessing that it is...
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    Quadratic Approximation of Potential Function using Taylor Expansion Method

    So for my first try I got U=(1.25)x2-10x+60. I am pretty sure I remember something about only going out to the second order place to make it "quadratic" so I got. 40 for the first place, 0 zero for the first order, and 1.25x2-10x+20 for the second order. Does this look right?
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    Quadratic Approximation of Potential Function using Taylor Expansion Method

    Homework Statement What is the quadratic approximation to the potential function? Homework Equations U(x) = U0((a/x)+(x/a)) U0= 20 a=4 The Attempt at a Solution This is just the last part of a question on my engineering homework, I never learned Taylor expansions before even...
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    What is the Volume Charge Density in the Region with Given Electric Field?

    Homework Statement An electric field in the region r>a is given by Er=2ACos(\vartheta)/r3, E\vartheta=Asin(\vartheta)/r3, E\psi=0 where A= constant. Find the Volume charge density in the region. There is not picture. I am really lost on this one.
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    Vector and partial derivatives

    Right *bangs head against the wall*. The only difference on the homework sheet between the vector and the magnitude is the vector is in bold. My stupid mistake. -Thanks
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    Vector and partial derivatives

    Right, I got that part. But what is a partial derivative of 1/ a vector?
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    Vector and partial derivatives

    Homework Statement Two charges one located at P at the position (x,y,z) and P' at the position (x',y',z') Let f= 1/R. Calculate Fx= partial derivative of f with respect to x. Calculate Fx'= partial derivative of f with respect to x'. There are sub question involving the same thing with...
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    How can I prove the Laplace transform of t^n step by step?

    I know the final result, its on all the charts. But I need to show step by step how to get the solution. If someone could help out by getting me in the right direction or just plain giving me the answer, that would be much appreciated:smile:.
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