It would have been better if you had precisely mentioned what "u", "uo" and "us" are in the equation you have written. The equation is valid in all situations provided you know what "u", "uo" and "us" are in the given equation. This also matches with my previous statement about shifting...
Your last compound is wrong. The sulphur shall have a -ve charge due to accumulation of another pair of electrons and the carbonyl carbon shall have +ve charge. That should help you get the mechanism. Post that, think about the stability of the sulphur and how it can become more stable.
I really think you should go back to the drawing board and re-understand the principles of substitution and addition. In addition to the site that @Ygggdrasil mentioned, you could also look at the following site : http://www.chemguide.co.uk/mechmenu.html#top
Here is how I understood it when I learned it. Hope it helps you too.
When we compare oxoacids across a group the strongest oxacid is the one which has the highest EN. This is because if the element has high EN it can pull the shared electrons of O-Y bond with greater ease. Now oxygen, by...
If you have a good idea of how Doppler Effect works when one is at rest then just shift your reference frame to one in which either of the moving objects is at rest. Then the unknown problem turns into a known situation.
Point one I didnt get this statement from you.
Ions can't have anions. I think you had a moment of confusion and wrote something else other than what you intended.
Coming to the question, why don't we use the method of elimination? Since the NaOH is (aq) it can't be a strong enough oxidising...
@Chestermiller ... Hello!
I was just looking this problem up to understand the concept of entropy better and I was wondering if you could tell me what the advantages of the second method are over the first. Is it only that it allows us to let us use the limit (as in let it tend to anything we...
OK I am unable to figure this out. I don't know what it tells me about the reaction, but I do understand that NH4+ and NO3- react.
No. They remain as they are and form NH4NO3. Does this mean they are not the reactants? OK I could listen to epenguin and google it up. But I don't like Google...