S is a portion of a curve with r(u,v)
where 0 < u < 2 and 0 < v < 2pi
I'm meant to calculate Flux of the vector field F
My Calculations
First found dr/du
then dr/dv
Using the cross product, I found N = (- u cos (v) + 5 sin (v), -5 cos (v) - u sin(v), u)
Then I dot product with the given...
Well the sample vectors came from the differential equation
And I already know how I can use that to find the field lines
But the question says to sketch and hence find the field lines, so I thought this way wouldn't be allowed.. :/
Well just the shape made it look like parabolas when I joined the dots... I know that the vectors that I have plotted for each point is the curve's tangent vector. And that the curve is defined by the position vector r(t)
Is there something else I'm missing?
Basically I've been given a vector equation, V(x,y) and different points to draw the vector field with directional arrows at each point. The question seems to indicate that by sketching the field lines passing through these points I should be able to find the associated differential equation...
Homework Statement
Is it possible to find the vector field line expression without the use of differential equations?
Say I've sketched the field and found the shape to be parabolas, how would I find the general expression by just using the points I've been given?Homework Equations
The Attempt...
Homework Statement
Plane: 4x−2y+10z =16.
Homework Equations
The Attempt at a Solution
So I've used two parameters, "u" and "v" with x = u and y = v
Re-arranging z in terms of "u" and "v": z = 1.6 - 0.4x + 0.2y
Hence r(t) = (u , v , 1.6 - 0.4 x + 0.2y)
Is this correct?
Homework Statement
Find the work done by a force acting in the direction 2i - 5j + k in moving a particle from (3, 3, 1) to (1, 2, 4).
Homework Equations
The Attempt at a Solution
I just found the displacement vector (2,1,-3) and did the dot product with the force vector...