- #1
dan38
- 59
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If I had a sphere centred at the origin with x > 0, y > 0 and z > 0
Would the angle boundaries be:
0 < θ < pi/2
0 < α < pi/2
?
Would the angle boundaries be:
0 < θ < pi/2
0 < α < pi/2
?
dan38 said:If I had a sphere centred at the origin with x > 0, y > 0 and z > 0
Would the angle boundaries be:
0 < θ < pi/2
0 < α < pi/2
?
Cartesian boundaries use x, y, and z coordinates to define a point in 3-dimensional space, while spherical boundaries use radius, inclination, and azimuth angles to represent a point on a sphere.
Converting from cartesian to spherical boundaries can be useful in certain mathematical or scientific applications, such as in physics or engineering, where spherical coordinates may be more appropriate for representing data or solving equations.
The formula for converting from cartesian coordinates (x, y, z) to spherical coordinates (r, θ, φ) is: r = √(x² + y² + z²), θ = arccos(z / √(x² + y² + z²)), and φ = arctan(y / x).
While spherical boundaries can be useful in certain applications, they may not be as intuitive or easy to visualize as cartesian boundaries. Additionally, spherical coordinates may not be suitable for representing points in non-spherical shapes or objects.
Yes, spherical coordinates can be converted back to cartesian coordinates using the formula: x = r * sin(θ) * cos(φ), y = r * sin(θ) * sin(φ), and z = r * cos(θ).