Recent content by Dark_Dragon

wouldn't you get: v = (F - E) / B ?

Homework Statement so, the question is basically asking me to rearrange F = qE + qvB to find 'v'. The Attempt at a Solution I'm not the greatest at rearrangements, but here is my attempt. F - qvB = qE F - v = qE / qB (q values cancel each other out) v = (E / B) + F is this right...

ok thank you so much for your help =)

period of rotation of Mars = 8.86 x 10^4 s mass of Mars = 6.42 x 10^23 kg Radius of Mars = 3.40 x 10^6 m if i use v=2πr/T v = 2*π*3.4e+6 / 8.86e+4 =241.1 m/s wait, so would my new equation be: r³ = GM/v² ? or would i have to go back a few steps and turn it into: 4π²r/T² =...

NASA wants to fire a satellite into a circular orbit around Mars that will maintain 'station' above the Martian equator. what is the distance from the surface of mars? ok first of all does the term 'station' refer to when g = 0? and the equation I've used is: Fc = Fg mv²/r = GMm/r²...

ok scratch the last post, i got it, thank you for your help both of you! much appreciated =)

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ok thank you very much :) i have a fair bit of trouble with rearrangements, so thanks for the help! =)

so you're saying that i need to turn the expression into R^3/T^2? then would the equation be: M = (4pi^2)(R^3/T^2) / G ? am i any closer?

after having a look at it for a while, i tried one step at a time and i came out with: M = (4*pi^2)(T^2/R^3)/G is this any better? please don't take offence if i didnt understand your post.

well i have my equation T^2/R^3 = 4pi^2/GM and i want to find 'M' on its own, (i never have been good at this) but here is my attempt: M = 4pi^2/G(T^2/R^3) is this correct?

aww man i didnt even think of it, thanks very much mate :)

An astronaut standing on the surface of the moon experiences a gravitational force of attraction of 160 N. He then moves away from the surface of the moon to an altitude where gravitational force is 40 N. a) How far away from the centre of the moon is this new location in terms of the radius...