Recent content by davi2686

Thanks Simon Bridge, I am already seen before the wikipedia article but is the only place until now I am read about spinor space as a complex vector space, because of this i had a doubt about the statement. (1) So complex vector space and spinor space are the same thing or spinor space are a...

Thanks very much to all, especially Zinq. I am think its time to read carefully your last answer to me and read the notes you had linked before playing thoughtless questions. I am really appreciate your help it helped me a LOT, thanks. .

Hi, i don't find much about spinor spaces. I can think in that spaces like a vector space above the field of complex numbers (a complex vector space)? sorry if what i saying is a non-sense, but i really want to understand better the math behind the concept of a spinor. thanks

Thanks very much Wrobel and Zinq. So let me see if i understand, (1) a differentiable structure is a map of a set into itself where this map is k-differentiable, (2) this implies that set is also a manifold (if k=infinite a differentiable manifold) (3) and if that set also a group, so we...

I learned a lie group is a group which satisfied all the conditions of a diferentiable manifold. that is the real rigour definition or just a simplified one? thanks

thank you very much, with your help I got what I wanted

I still can't find a book with properties and theorems involving block matrices multiplication to reference in my undergraduate work. thanks

Thanks i did not know that. That is musical isomorphism \flat:M \mapsto M^*, in fact i understand it works like a lower indice, \vec{B}^{\flat} give me a co-variant B or it related 1-form.

my initial motivation is in Gauss's Law, \int_{\partial V} \vec{E}\cdot d\vec{S}=\int_V \frac{\rho}{\epsilon_0}dV, i rewrite the left side with differential forms, \int_{\partial V} \star\vec{E}^{\flat}=\int_V \frac{\rho}{\epsilon_0}dV which by the Stokes Theorem \int_{V}...

thanks, but have no problem with 0 is a 0-form and d\omega a k-form? so can i work with something like d\omega=4 ?

if i have \int_{\partial S} \omega=0 by stokes theorem \int_{S} d \omega=0, can i say d \omega=0? even 0 as a scalar is a 0-form?

sorry at the moment i can't think another way to put what i need

Hi JonnyMaddox, do you know some book which talks about pseudoforms?

Be a vector field \vec{F}=(f_1,f_2,f_3) and \omega^k_{\vec{F}} the k-form associated with it , i know if i do \int \omega^1_{\vec{F}} is the same of a line integral and \int \omega^2_{\vec{F}} i obtain the same result of \int \int_S \vec{F}\cdot d\vec{S}, which is the flux of a vector field in a...

if i have a vector field \vec{F}=(f_1,f_2,f_3),i know which for obtain 1-form associated with it i do \vec{F}^{\flat}=f_1dx^1+f_2dx^2+f_2dx^3, but how can i get the 2-form and p-form associated with that vector field? And one more thing, the musician isomorphisms which i used is only valid in...