The 2nd question. Find it yourself, it must be this equation you are to use, else it is complicated I think.
3rd question: Newtons 1st law says that a particle which is affected by no force is continuing with the same velocity along a straight line, thus if it had e.g. v = 400m/s as velocity it...
Equilbrium is when there is no motion right? So torques must cancel out and all forces aswell, this leaves two vectorial equations:
\sum\mathbf{\tau} = \vec{0}
\sum\vec{F} = \vec{0}
Now the picture has two wires holding it up. The weight of the picture is w = mg (in y dir.)...
So the magnetic force is \vec{F} = q\vec{v}\times \vec{B}
q is the positive charge. I do not know what straight ahed means, I assume that you have a sketch. Your thumb on the right hand shall be in the direction of the velocity and your index finger along the magnetic field, then your middle...
I think that since you are working with idel gasses, you can dervie most of the stuff from 3-4 equations, namely:
The ideal gas law : pV = nRT
The Laws of thermodynamics.(2-3 laws is useful).
If you want to find the Work done during a isothermal(T constant) step e.g.:
W =...
Homework Statement
I have an energy function as follows:
E = \dfrac{\hbar^2}{2m_e}k_x^2+E_0\left(n_y^2+1\right)
Where E_0 = \dfrac{\pi^2\hbar^2}{2m_eL_z}
I am asked to plot this energy for x\in ]-L_z/2;L_z/2[
I know everything but not the relation between k and x?.
The Attempt at a...
You need to make an attempt to solve the problem, but in general,
1. write down your generalized coordinates i.e. identify and use your constraints.
2. write the potential and kinetic energies of the system
3. find L = T-V, where T =kinetic and V = potential and L = lagrangian
4. Write the Euler...
You didn't post the diagram.
Lentz's law isn't the appropriate one. You need to use Faradays law: "change in magnetic flux induces a current"(tries to oppose the change in magnetic flux according to lenz law)
So it induces an EMF which should result in an opposing magnetic flux.
So Lenz's law...
Use energy conservation instead? It is relativley easy with that. Then divide the problem into 2 sections
1. Find the max height from the total energy with 0-potential at the groud:
mgh_{window}+\dfrac{1}{2}mv_0^2 = mg(h_{max}+h_{window})
\dfrac{1}{2}mv_0^2 = mgh_{max}
h_{max} =...
You use Newtons 1st law first:
T_A+T_B+T_C - mg - P = 0
Then the sum of Torques should also be zero at the limit:
\vec{P}\times \vec{d} + \vec{T}_A\times \vec{r_A} +\vec{T}_B\times \vec{r_B} + \vec{T}_C\times \vec{r_C} = \vec{0}
And use that the magnitude of the cross product of two vectors...