Prove n =1 for pv^n=C, when temperature is constant

Click For Summary
SUMMARY

The discussion focuses on proving that an isothermal process can be classified as a specific case of a polytropic process, specifically demonstrating that the value of n equals 1 under constant temperature conditions. The equations used include P1V1n = mRT1 and P2V2n = mRT1, leading to the conclusion that P1V1n = P2V2n. The participant expresses uncertainty about the proof but acknowledges the need to establish n=1 definitively for isothermal processes.

PREREQUISITES
  • Understanding of isothermal processes in thermodynamics
  • Familiarity with polytropic processes and their equations
  • Knowledge of the ideal gas law and its applications
  • Basic algebraic manipulation skills for thermodynamic equations
NEXT STEPS
  • Study the derivation of the polytropic process equation P1V1n = const
  • Research the implications of constant temperature in thermodynamic systems
  • Explore the relationship between pressure, volume, and temperature in ideal gases
  • Investigate real-world applications of isothermal and polytropic processes in engineering
USEFUL FOR

Students and professionals in thermodynamics, mechanical engineers, and anyone studying the behavior of gases under varying conditions will benefit from this discussion.

nu_hash
Messages
10
Reaction score
0

Homework Statement



Show that an isothermal process can be regarded as a special case of a polytropic process and deduce what value of n applies in this case.

Homework Equations



P_{1}V_{1}^n = const


The Attempt at a Solution


P_{1}V_{1}^n = mRT_{1}
P_{2}V_{2}^n = mRT_{1}

(since temperature is constant T_{2} = T_{1})

therefore:
P_{1}V_{1}^n = P_{2}V_{2}^n

but i don't think this proves that n=1 for a isothermal process
 
Physics news on Phys.org
Edit: What I wrote was nonsense sorry.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
49
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K