Recent content by DLH112

I know light behaves oddly compared to normal matter, I haven't really delved into the math of GR, and that's why I'm here to ask these questions. 1) If all of our observations of the universe are based on light, what determines that the speed of light is the maximum velocity? I'm sure its...

oh wow, thanks, I am blind xD

its an online homework thing. it said that answer is wrong

ah i see. something like mgh = mL and the mass cancels so gh = L or h = L/9.8 edit: 9.8 m/s2 h = 330000 J/kg h = 330000/9.8 h = 3367.46939 m or 3.367469 km? this is wrong though... maybe i got some units wrong?

Homework Statement Assume that a hailstone at 0◦C falls through air at a uniform temperature of 0◦C and lands on a sidewalk also at this temperature. From what initial height must the hailstone fall in order to entirely melt on impact? The acceleration due to gravity is 9.8 m/sec2 and the...

that makes sense... so it would be like (0.03)^3 then i guess

Homework Statement A cork is held at the bottom of a bucket of water by a piece of string. The actual depth of the cork is 0.713786 m below the surface of the water. If the density of the cork is 157 kg/m3 and the volume of the cork is 3 cm3 , then what is the tension in the string...

ah thank you. i was accidentally using 28.6 instead of 26.8.

Homework Statement This is a 3 part problem and I've successfully solved the first 2 parts, but I don't know what I did wrong in the third part. 1) mass of 346 g on a spring with constant 26.8 N/m on a horizontal + frictionless surface. Amplitude is 6.7 cm. In part 1 i found the total...

Homework Statement find the mass of an unevenly distributed bar with length 2 meters whos mass at a point is given by an equation 0.6 + x^2. Then find the center of mass. Homework Equations The Attempt at a Solution I got the first part (finding the mass) correctly, but I can't...

so if L= Iw and I = 1/2 MR^2 then you get L = (0.5) (131) (1.4) (0.7539822). but wouldn't w need to go to infinite if R is 0?

Homework Statement A merry-go-round rotates at the rate of 0.12 rev/s with an 86 kg man standing at a point 1.4 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 45 kg cylinder of...

I must've been tired and mixed up the 16.6 kg and 26 degrees, so i used 26.6 degrees when calculating instead. i feel dumb xD

sure. mg = (9.8)(16.6)= -162.68 N Fy = 161 sin(26.6) = 72.08921314 N so Fnet down/ -Fn = -90.59078686 N then W(fric) = (39.1)(0.181)(90.59078686) = -641.1200577 J

Homework Statement There's a mass (16.6 kg) on a surface with kinetic coeficient of friction 0.181. it's being pulled by a constant force of 161 N at 26 degrees above the horizontal. The block is displaced 39.1 meters. Calculate the work done by friction.Homework Equations Friction = (mu)Fn...