What Is the Velocity of a Mass on a Spring When Displacement Is 3.6 cm?

AI Thread Summary
The discussion focuses on solving a physics problem involving a mass on a spring, specifically calculating the velocity when the displacement is 3.6 cm. The total energy was correctly calculated as 0.0601526 J, and the maximum speed was found to be 0.58966337 m/s in previous parts. The user attempted to apply the energy conservation equation but initially made an error by using the wrong spring constant value. After identifying the mistake, the correct spring constant of 26.8 N/m was confirmed, leading to a reevaluation of the velocity calculation. The discussion emphasizes the importance of accuracy in using constants and formulas in physics problems.
DLH112
Messages
19
Reaction score
0

Homework Statement


This is a 3 part problem and I've successfully solved the first 2 parts, but I don't know what I did wrong in the third part.

1) mass of 346 g on a spring with constant 26.8 N/m on a horizontal + frictionless surface.
Amplitude is 6.7 cm. In part 1 i found the total energy to be 0.0601526 J. and in part 2 i found the max speed to be 0.58966337 m/s.

part 3 is "What is the magnitude of the velocity of the mass when the displacement is equal to 3.6 cm? answer in m/s"

Homework Equations


E = KE + PE , 1/2KA^2 = 1/2kx^2 + 1/2mv^2


The Attempt at a Solution


using the energy from part 1 as E...
0.0601526 = (0.5)(26.8)(0.036)^2 + (0.5)(0.346)v^2
0.061526 = 0.0185328 + (0.5) (0.346)v^2
0.0416198 = (0.5)(0.346)v^2
0.2405768786 = v^2
0.4904863694 m/s = V ... is apparently wrong
 
Physics news on Phys.org
DLH112 said:
using the energy from part 1 as E...
0.0601526 = (0.5)(26.8)(0.036)^2 + (0.5)(0.346)v^2
0.061526 = 0.0185328 + (0.5) (0.346)v^2
Double check the highlighted term.
 
ah thank you. i was accidentally using 28.6 instead of 26.8.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top