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    Thermodynamics (Kelvin-Planck statement )

    So,... although energy absorbed by the gas is completely converted to work, the energy is disordered, and so the energy is not actually conserved. Is that what you mean??
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    Thermodynamics (Kelvin-Planck statement )

    Hi, I got a problem in thermodynamics. Q. In an isothermal expansion of a gas the energy absorbed by the gas is completely converted to work. Explain how this process can still be consistent with the Kelvin-Planck statement of the second law of thermodynamics. I thought that's because the...
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    Mistake in proof of gravitational potential equation?

    mistake in proof of gravitational potential equation? Hi, I have a problem in deriving an equation for the gravitational potential. Well, I think that the graviational potential is the work done by external forces in moving a unit mass Mp from infinity to that point through distance d, and...
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    Conservation of Momentum in an Isolated System: A Derivation

    well, does that mean -ma=ma for representing the situation where two particles collide? but i still don't understand how to proceed tp get initial total momentum =final total momentum
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    Conservation of Momentum in an Isolated System: A Derivation

    Homework Statement Derive a law of conservation of momentum for an isolated system consisting of two interacting particles. Homework Equations It says that "The law is derived by applying Newton's second law to each particle and Newton's third law to the system." The Attempt at a...
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    Wave-like Properties of a Cadillac Passing Through a Freeway Underpass

    ah-huh, i kind of understood the question now. Thank you!
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    Wave-like Properties of a Cadillac Passing Through a Freeway Underpass

    Homework Statement A Cadillac with a mass of 2000kg approaches a freeway underpass that is 10m across. at what speed must the car be moving, and how long would it take to go the 10m, in order for it to have a wavelength such that it might somehow diffract after passing through this single...
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    Calculate the energy of the proton

    Homework Statement A proton moves in a circular path perpendicular to a 1.15T magnetic field. The radius of its path is 9.3mm. Calculate the energy of the proton in eV. Homework Equations F=ma=mv^2/r, F=qvB The Attempt at a Solution F=ma=mv^2/r=qvB mv/r=qB...
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    What is the final velocity of two point charges moving away from each other?

    Oh, I got it! So if the charges are, for example +10uC and +20uC, then the velocity of charge (+10uC) would be v=(W/3*2/10^-6)^0.5, right?
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    What is the final velocity of two point charges moving away from each other?

    But how do you know that each charges only carries W/2 KE? I don't quite understand that...
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    What is the final velocity of two point charges moving away from each other?

    Homework Statement 2 identical +10uC point charges are initially spaced 5.5cm from each other. If they are released at the same instant from rest, how fast will they be moving when they are very far away from each other? Assume they have identical masses of 1.0mg. Homework Equations...
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    Calculating Work Required to Move Test Charge

    Oh, I finally got the right answer, following Mr/Ms Mentz114's way! Thank you so much! But...I still can't understand why the energy in both directions are added together for calculating the potential energy. Aren't the charges at right and left end both positive? Then don't they exert equal...
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    Calculating Work Required to Move Test Charge

    So the initial PE is net initial force =2*((0.5*10^(-6))(30*10^(-6))k/0.2^2 =6.7425 PE=F/q=6.7425/(0.5*10^(-6))=13485000 W=qEd=(0.5*10^(-6))*13485000*0.2=1.3485 net final force =((0.5*10^(-6))(30*10^(-6))k/0.1^2 +((0.5*10^(-6))(30*10^(-6))k/0.3^2=14.9833...
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    Calculating Work Required to Move Test Charge

    I tried with W=qV=(0.5*10^(-6)){(30*10^(-6)k/0.1)(30*10^(-6)k/0.2)} but the answer was then too big... I then assumed that the potential energy is 0 when the test charge is sitting between the two +30uC charges (as it's balanced). And the energy when it is moved 10cm over is: force...
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