1. The problem statement, all variables and given/known data A proton moves in a circular path perpendicular to a 1.15T magnetic field. The radius of its path is 9.3mm. Calculate the energy of the proton in eV. 2. Relevant equations F=ma=mv^2/r, F=qvB 3. The attempt at a solution F=ma=mv^2/r=qvB mv/r=qB v=qBr/m=1.6*10^-19*1.15*0.0093=1022833 F=qvB=1.6*10^-19*1022833*1.15=1.882*10^-13 I don't know how to convert F to the energy... Well, first of all, am I correct so far?