(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A proton moves in a circular path perpendicular to a 1.15T magnetic field. The radius of its path is 9.3mm. Calculate the energy of the proton in eV.

2. Relevant equations

F=ma=mv^2/r, F=qvB

3. The attempt at a solution

F=ma=mv^2/r=qvB

mv/r=qB

v=qBr/m=1.6*10^-19*1.15*0.0093=1022833

F=qvB=1.6*10^-19*1022833*1.15=1.882*10^-13

I don't know how to convert F to the energy...

Well, first of all, am I correct so far?

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# Homework Help: Calculate the energy of the proton

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