Recent content by dphysics

Thank you, haha yes I was over analyzing it way too much, I missed that. Thanks again!

Homework Statement Calculate the equivalent impedance about terminals A and B. [PLAIN]http://img218.imageshack.us/img218/9335/circuits827.png Z1 = -j2 ohms Z2 = 1 ohm Z3 = j2 ohms Z4 = 2 ohms Homework Equations Adding parallel: Zeq = z1*z2/z1+z2 Adding in series Zeq = z1+z2...

Gear, would you treat the current source as a separate voltage source altogether or combine it with the surrounding resistor and use it in the equation V=IR?

When you are using Kirchhoff's voltage law and you come across a current source, what are you supposed to include that as? Pretending that it is an ideal current source, there will be no resistance and thus no voltage drop. So, do you just ignore it in the voltage equation? (Ex: V1+V2+V3=0)...

Homework Statement The voltage across and current through a certain device are given by: v(t) = 5cos(4*pi*t) i(t) = .1cos(4*pi*t) Determine: (a) the instantaneous power p(t) at t= 0 and t = .25 seconds (b) the average power pav, defined as the average value of p(t) over a full time period of...

It mentions in an earlier part of the problem that the velocity is 9.40×106, however it doesn't specify if that remains constant throughout the problem. Assuming for a moment that it does, let's try to plug that into the equation: F = qvBsin(theta) F = 1.609E-19 * 9.40×106 * 87E-3 (I'm...

Ah alright, that does make sense then. How would I go about calculating the velocity though? qvb = F F = ma qvb = ma v = 8243000 qvB/ma = sin(theta) qvB/ma = 1, giving you theta = 90 degrees. This unfortunately is incorrect.. =\

I just checked again, and those are the correct values for a and B.

Hmm, that is what I have above, at least I think. Because when you substitute F = ma into F = qBsin(theta), you end up with ma = qbSin(theta), which can be arranged to sin-1(ma/qb) = Theta. The values I used: m = 9.1E-31 kg q = 1.609E-19 C B = 87E-3 T a = 1.268E17 I still end up calculating...

Homework Statement The acceleration of an electron in a magnetic field of 87 mT at a certain point is 1.268×1017 m/s2. Calculate the angle between the velocity and magnetic field. Homework Equations F = q dot v cross B F = qBsin(theta) F/m = a The Attempt at a Solution I...

Ah thanks a lot, figured it out :)

Homework Statement A singly charged proton ion of 7 Li has a mass of 1.16E-26 kg. Starting from rest it is accelerated in the positive x-direction through a potential difference of 165 kV. The ion then enters a uniform magnetic field that has magnitude 0.325 T and is directed in the negative...