Recent content by EchoTheCat

Resistors 2 and 5 form a series circuit on the right side; their combined resistance is 14. This is parallel to Resistor 3; their combined resistance is 1/R = 1/7 + 1/14 --> R = 4.66667. The three resistors now in series are 1, 4, and combined resistors of 2, 3, and 5. The sum of the resistance...

Here's the picture. I did try considering the circuit as a parallel circuit R1, R3, and R4 together with total resistance 21 and R2 and R5 together with total resistance 14 but that didn't work

Homework Statement Consider the electric circuit shown in the figure. Assume that V = 13.7 V, R1 = R2 = R3 = R4 = R5 = 7.00 Ω. What is the equivalent resistance of the circuit? Homework Equations total voltage of a series circuit is the sum of the voltage of all the resistors total current of...

Homework Statement A person turns up the volume on a radio. Which aspects of the motion of a point on the diaphragm must increase? a. maximum displacement only b. average speed only c. both maximum displacement and average speed d. neither maximum displacement nor average speed Homework...

Ok, so I was able to solve for (m1g+m1a)R – (m2g-m2a)R = -(1/2mr2)a, so, a = 6.37 rad/s/s.

Homework Statement There are two blocks, m1 and m2, that are hanging from a rope which passes over a pulley. The mass of the pulley is 0.15 kg. The radius of the pulley is 0.055 m. The mass of m1 is 0.165 kg. The mass of m2 is 0.18 kg. The linear acceleration is m1 is 0.3504 m/s/s downward, and...

Homework Statement A block of mass MB = 0.7 kg hangs from a string wrapped around a hoop that can rotate around its center. The hoop has a mass of MH = 1.3 kg and a radius of R = 0.4 m. The block descends under the influence of gravity. What is the magnitude of the acceleration of the mass in...

The torque from 2.04 meters on the left side and 2.04 meters on the right side would cancel out. Then, we are left with 0.42 meters on the right side. 0.42 meters*9.8m/s/s*mass of the beam, since T = Fr. The center of mass of the beam would be at 2.25 meters.

BvU this is what my sketch looks like.

Homework Statement Determine the mass of a 4.5 meter beam, if it is balanced on a fulcrum 2.04 meters from the left end. A 886 N man stands on the very left end, and a 393 N girl stands on the right end. [/B]Homework Equations T = Fr The Attempt at a Solution The torque applied by the man...

Fk = 3.9159 Fn = 5.219 uf = Fk/Fn = 3.9159/5.219 = 0.750

3.9159/5.219 = 0.750 [SIZE=16px][FONT=PT Sans]

Wouldn't Fk = Fgx - Fa = 6.1106 - 2.195 = 3.9156 N?

I need to calculate Fk, the force of kinetic friction.

net force = mass x acceleration