Recent content by EL ALEM

I already got it, it was late and I wasn't thinking straight, thanks for the replies though.

Homework Statement (1/x)^x - x = 0 Homework Equations The Attempt at a Solution (1/x)^x - x = 0 (1/x)^x = x xln(1/x) = lnx Thats all i got up to, I just need a kick in the right direction so I can finish it up.

Homework Statement Nother Q for today: Let f(x)= (1/x)^x - x (a)show that f(x)=0 has a solution (b)show that there is only one solution to f(x)=0 (c)use Newton's Method to find the second approximation x2 of the solution to f(x) = 0 using the initial approximation x1 = 1/2 Homework...

ok tried it, but I am having trouble b/c of the sqr root

thanks! ill try it out.

Homework Statement evaluate the lim as x->0 of [sqroot(tan3x)+srroot(sin2x)]/sqroot(tan2x) WITHOUT using L'Hospital's Rule Answer is sqrt3/2 + 1 This is in the exam review for my class, and I am having a hard time getting started on this one. Thanks in advance. Homework Equations...

Forget that, I figured it out. I started it off kinda wrong.

Homework Statement Solve the inequality: e^(2-3x)>4 Homework Equations none The Attempt at a Solution would i start of like this? e^(2-3x)>4 ln(2-3x)>ln4 if so how do i continue?

Ok thanks.

Thanks a bunch, one more question, if it was only less than instead of less than or equal to how would we divide the set into intervals?

Ok so i found 2cosx + 1 < 0 at this interval (2pi/3, 4pi/3) , so would that be my answer?

Homework Statement find all values of x in the interval [0, 2pi] that satisfy the equation 2cosx + 1 less than or equal to 0 Homework Equations None. The Attempt at a Solution for when 2cosx+1=0 cosx=-1/2 x= 2pi/3, 4pi/3 but what about the values for when 2cosx + 1 is less then...

Yup that cleared A LOT of things up. Thanks a mill.

Ok is it the same thing for sin and cos? thanks in advance.

Yup thanks for the reply, I ended up doing using the quadratic formula and ended up simplifying nicely (i got tanx= -sqrt3/3, sqrt3) but one question how would i find ALL the values on [o,2pi], i know how to find the ones in the first quadrant (i.e. tanx= sqrt3 => x=pi/3 ) but how do i find...