Help with Limits Homework: Evaluate sqrt(tan3x)+sqrt(sin2x)/sqrt(tan2x)

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Homework Statement


evaluate the lim as x->0 of [sqroot(tan3x)+srroot(sin2x)]/sqroot(tan2x) WITHOUT using L'Hospital's Rule
Answer is sqrt3/2 + 1

This is in the exam review for my class, and I am having a hard time getting started on this one. Thanks in advance.


Homework Equations





The Attempt at a Solution

 
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i would divide it into 2 separate limits & try some trig angle sum indentities
 
thanks! ill try it out.
 
Last edited:
ok tried it, but I am having trouble b/c of the sqr root
 
\lim_{x\to 0} \frac{\sqrt{tan3x}+\sqrt{sin2x}}{\sqrt{tan2x}} <br /> = \lim_{x\to 0} \left \sqrt{\frac{tan3x}{tan2x}} +\sqrt{\frac{sin2x}{tan2x}}

so all the operations should be within the sqrt's
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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