Recent content by emhelp100

Why is the red line +x-y?

no

Homework Statement Two uniform infinite sheets of electric charge, one with charge density +o and the other with -o, intersect at right angles. Find and sketch the electric field \vec{E} Homework Equations \vec{E} = \frac{\sigma}{2e_0} The Attempt at a Solution Given solution: [/B]...

Homework Statement Four equivalent charges are placed at (0,0), (a,0), (0,a), and (a,a). What is the electric field at point B (a, a/2)? Homework EquationsThe Attempt at a Solution My attempt: Charges at (a,a) and (a,0) cancel each other out. E_{(0,a)}= \frac{Q(\hat{x}a...

I don't see it...

What does this mean? For E1 and E3, the x^ direction integral canceled out. For E2 and E4, the y^ direction integral canceled out.I am left with: \int_{\frac{-a}{2}}^{\frac{a}{2}}\frac{\hat{x}\frac{a}{2}}{(\frac{a^2}{4}+y^2)^{3/2}}dy -...

\int_{\frac{-a}{2}}^{\frac{a}{2}}\frac{\hat{x}\frac{a}{2}}{(\frac{a^2}{4}+y^2)^{3/2}}dy+\int_{\frac{-a}{2}}^{\frac{a}{2}}\frac{\hat{y}y}{(\frac{a^2}{4}+y^2)^{3/2}}dy

So now that I have this: \int_{\frac{-a}{2}}^{\frac{a}{2}} \frac{\hat{x}\frac{a}{2}+\hat{y}y}{(\frac{a^2}{4}+y^2)^{3/2}}dy How do I integrate this?

Not really sure what it would be in rectangular coordinates...

Homework Statement A point charge +Q exists at the origin. Find \oint \vec{E} \cdot \vec{dl} around a circle of radius a centered around the origin. Homework EquationsThe Attempt at a Solution The solution provided is: \vec{E} = \hat{\rho}\frac{Q}{4\pi E_0a^2} \vec{dl}=\hat{\phi}\rho d\phi...

So would this setup be correct? E1 = E3 = \frac{Q}{4\pi E_0} \frac{\hat{x}{x}+\hat{y}\frac{a}{2}}{(x^2+\frac{a^2}{4})^{3/2}} dl1=dl3 = \hat{y}dy E2 = E4 = \frac{Q}{4\pi E_0}\frac{\hat{x}\frac{a}{2}+\hat{y}{y}}{(y^2+\frac{a^2}{4})^{3/2}} dl2=dl4 = \hat{x}dx

That is because x stays constant and y changes right?

E1 is the line segment from (a/2,-a/2) to (a/2, a/2)

Homework Statement A point charge +Q exists at the origin. Find \oint \vec{E} \cdot \vec{dl} around a square centered around the origin. I know the answer is 0, but can someone check my setup? Homework Equations E=\frac{Q(\vec{R}-\vec{R'})}{4\pi E_0 |\vec{R}-\vec{R'}|^3} The Attempt at a...