Ok, so what's the difference if I use 60 terms, which gives me about 99% of the power in the signal versus using 20 terms which gives me about 95% of the power in the signal? When the ultimate goal is to have the smallest bandwidth. I guess the gibbs phenomenon is still present in either case...
How does the Gibbs Phenomenon effect the choice of the kth harmonics for bandwidth selection?
Basically, I have plotted a square wave using the Fourier series analysis for choosing the kth harmonics. As, I increase the kth harmonics the oscillations increase. What is the smallest harmonic i...
Homework Statement
Derive the second order differential equation relating x(t) and y(t).
Using the Laplace transform, find the total response as a function of the zero input response and the zero state response in the following form.Homework Equations
Y(s)=Yzs(s) + Yzi(s)
The Attempt at a...
What are the cell potentials of the following?
1) ZnSO4 (1M) & CuSO4 (1M)
2) ZnSO4 (1mM) & CuSO4 (1mM)
3) ZnSO4 (0.1M) & CuSO4 (1M)
I tried using the nearst equation and I keep getting that they are all the same value of +1.10V
Hold on. I think I got it. But how are getting the probability of getting a match to one of three previous cards out of the remaining 5? You have (1/3). I say it is (3/5) because there are three chances of getting a match to anyone of the three cards..
The probability of stopping at the third draw is 2/6? So the probability of stopping at the fourth draw is (1-2/6)? So this times the probability of getting a match to one of the first three cards out of the remaining five is (3/5)? But (2/3) * (3/5) is 2/5. But the answer in the back of the...
The probability of stopping at the fourth draw is, again, the probability you haven't stopped in the first three (1-6/7)?, times the probability of getting a match to one of the first three cards out of the remaining five (3/5)?. I'm am a little confused on how to calculate the probability I...
The probability of stopping at the first draw is 0. (because you have only drawn one ticket). The probability of stopping at the second draw is 1/7 (because out of the 7 remaining cards their is only 1 possibility for a duplicate of the first). The probability of stopping at the third draw is...
Homework Statement
A box contains 8 tickets. Two are marked 1, two are marked 2, two marked 3, and two marked 4. Tickets are drawn at random from the box without replacement until a number appears that has appeared before. Let X be the number of draws that are made. Make a table to display the...
Homework Statement
Determine the voltage Vx and the power absorbed or supplied by each source
Determine the current Iba and the voltage Vba
Homework Equations
KVL
The Attempt at a Solution
I tried doing KVL for the right side of the arrow to try and find Vx, but i get terms of (I)...
Homework Statement
Treat the circuit as a two node problem and determine the voltage between the nodes.
Express Ix and the current through the 6k resistor in terms (as functions) of the current Il and use KCL
Homework Equations
KCL and ohms laws
The Attempt at a Solution
I used...
I had a question. When you have a circuit with a independent current source and a voltage dependent current source. And the dependent current source is dependent on the Voltage drop across the independent current source. How do I solve for this voltage drop when the currents are in parallel...
Ok I used the loops ad, be, dg, ef. All going clockwise from the node.
to get 4 equations and I set them equal to zero. however, from those four equations. you can't solve for any unknown variable. Please let me know if this is solvable as I have tried several different ways and can't come...