RLC Circuit Second Order Differential and Laplace

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Discussion Overview

The discussion focuses on deriving the second order differential equation for an RLC circuit and using the Laplace transform to find the total response as a function of the zero input response and the zero state response. The scope includes mathematical reasoning and homework-related problem-solving.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The initial attempt involves setting up equations based on loop analysis for the RLC circuit, leading to a system of differential equations.
  • One participant suggests solving for i1 in the second equation and substituting it into the first equation, proposing to express the equations in terms of y(t).
  • Another participant identifies a potential error in the sign of the term Rload*i2, arguing that it should be negative based on the direction of current flow through the capacitor.
  • A later reply agrees with the need for a negative sign in the expression for y(t), clarifying that it depends on the assumed direction of i2.

Areas of Agreement / Disagreement

Participants express differing views on the sign of the term Rload*i2, indicating a lack of consensus on this aspect of the equations. The discussion remains unresolved regarding the correctness of the equations and the assumptions made about current directions.

Contextual Notes

There are unresolved assumptions regarding the direction of current flow and its impact on the signs in the equations. The participants have not fully verified all steps in the derivation process.

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Homework Statement


Derive the second order differential equation relating x(t) and y(t).
Using the Laplace transform, find the total response as a function of the zero input response and the zero state response in the following form.

Homework Equations



Y(s)=Yzs(s) + Yzi(s)

The Attempt at a Solution



Loop1: Rs*i1 + 1/c integral(i1 + i2) dt = xs(t)

Loop2: 1/c integral(i1 + i2) dtau + Rload*i2 + L di2/dt = 0

Take derivatives

Loop1: R di1/dt + (i1 + i2)/C = dx/dt

Loop2: R di2/dt + L di2/dt + (i1 + i2)/C = 0
 

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Try solving for i1 in the second equation and substitute into the first equation. Then use y(t)=Rloadi2 to rewrite the equation in terms of y(t).
 
Loop2: 1/c integral(i1 + i2) dtau + Rload*i2 + L di2/dt = 0

I believe there is an error here. If the current through the capacitor is i1 + i2, then i2 is moving counterclockwise, and we know as the current approaches the load resistor, it is approaching the negative end of y(t). Therefore, Rload*i2 should be negative. I haven't checked everything, so there could be more problems.
 
I think that equation is fine; it's correct if you assume i2 goes in the counterclockwise direction. But I should have said to use y(t)=-Rloadi2. I forgot the OP used the opposite direction than usual on i2.
 

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