Recent content by greyradio

Right. So I would use this formula: \Delta E = Ef - Ei So I would get this: Ef = 1/2 M_{satellite} V_{orbital speed}^{2} - GM_{earth}M_{satellite}/R The radius would be the radius of the Earth plus the height above the surface Ei = 1/2 M_{satellite} V_{initial}^{2} -...

I have another question relating to this problem 1.the work that was done to put the satellite into this orbit. Assume that it starts at rest on the surface of the earth. Friction is to be ignored. I have the orbital speed. Could the work-energy theorem be used? If so then it...

A 619 kg satellite is in circular orbit 7.84x106 m above the surface of the Earth. Find: a) the acceleration due to gravity created by the Earth at the distance of the satellite. correct check mark m/s2 b) the weight of a 70.4 kg astronaut inside the satellite. Equations: Fg = G M...

yeah I'm sorry i had to edit it a few times since some of the subscripts were displayed oddly. It worked out it thanks a lot for your help.

[SOLVED] Pulley problem (Rotation) Mass m1 = 9.07 kg sits on a frictionless, horizontal surface. A massless string is tied to m1, passes over a pulley (a solid disk of mass Mp = 5.42 kg and radius Rp = 37.9 cm), and is tied to m2 = 6.94 kg hanging in space. Find the acceleration of the masses...

thanks it worked out.

[SOLVED] Momentum problem Two astronauts float in space, at rest relative to each other. The first astronaut, mass 63.4 kg, holds a ball of mass 7.28 kg, which she throws at speed 6.17 m/s. The second astronaut, mass 83.1 kg, then catches the ball. Find the speed one astronaut is moving...

Thank you. I did not subtract the dissipated energy from the original. Thanks to all that helped.

[SOLVED] Conservation of Energy problem Assuming there is no air friction, A 1.4 kg ball is dropped from a height of 2.68 m. It hits the ground, losing 1/12 of its energy in the collision. How high will the ball bounce upward before it comes momentarily to rest? E = K sys + U sys Ef = Ei...

yeah it seems i was using the incorrect direction of the tension since it is opposite of the weight then it should be negative. Thanks.

[SOLVED] Work problem A vertical rope is used to lower a mass 44.9 kg at a constant acceleration of magnitude 4.57 m/s2. Find the work done by the tension in the cord if the mass moves down distance 2.66 m. W = F (change in X) First, I tried to get the tension by: -T + mg = ma -...

A plane is flying at a speed of 206 km/h in still air. There is a wind blowing at a speed of 76.6 km/h at 48.7 degrees to the east of north, and the pilot wishes to fly due north. What angle should the plane fly? (assume the angle is measured between the plane and north.) What speed does the...