Recent content by Guneykan Ozgul

Do you know Faraday's law? It says that ##\int{\vec{E}.d\vec{l}}## = -##\frac{∂Φ}{∂t}## where Φ is the magnetic flux. So the direction of the induced electric field is dependent on the sign of the change in magnetic flux.

What makes you think that it is 4y^3, what happened to x? Since the derivation is with respect to y the x will behave like a constant. So it's 4xy^3.

Okay, instead of going into Lagrangian let's apply Newton's laws directly but keep in mind that they are equivalent. For a series spring system the equivalent spring constant is k1k2/(k1+k2). You can derive this using the fact that the force on the two springs are equal. If you have difficulty...

Yes, it seems correct.

Have you tried to identify the forces acting on the mass? And what do you mean by acceleration between spring 1 and 2?

Since you can calculate the potential difference(emf), you can calculate the power with VI instead of going into resistance.

While calculating the electric field, the integral you wrote down is enough, after you calculate the electric field you can find the induced current density by J=δE (Ohm's Law).

The integral you wrote down is valid whatever the shape is however when you are trying to find the electric field fom that integral equation the shape matters. The disk allows you to conclude that the electric field will be dependent only on radius and the total length element 2*pi*r, so it...

Volume of the gas does not change if the tank is not elastic (I think not in this question) since the gas will always fill the whole tank.

Yes, the first but maybe inefficient solution that comes to my mind is as follows, You read the first file and put the values into a 2D array(think of it as a matrix) and then you can read the second file and put the values into the corresponding index of the 2D array and then you can write a...

From Snell's law n1sinα=n2sinβ where α is the angle of incidence and β is the angle between normal and beam in the water. Using the given info, sinα=√3/2=(x+1)\√(x+1)2+h2, from here you get x= √3h-1 and x=-√3h-1 (however this is negative, so not a physical solution) and...

Mathematically to make the the time taken for the ball hit the surface a linear function of displacement you should make velecity constant, hence 0 acceleration. For a free fall...

Okay. Now, let's say that acceleration is constant a . Now the velocity at time t will be at. Then the displacement d=∫atdt=1/2at^2 assuming that the initial position is 0. Now let's say that the ball hits the ground and the energy of the ball reduces to bE where E is the energy of the ball...

What do you exactly mean by the time taken for it to bounce? Is it the time taken for it to reach to the ground or to reach the ground and bounce a few times and stop due to loss of energy?

Ohh, sorry I did not see the part that asks you to write the sattalite radius as eta R. I think you should use @gneill 's argument.