Recent content by Heexit

Thanks for your help! Here is my solution:

Thanks for your help! The only equation that I can think of is: ##a_s=\frac {dv} {dt}## Anything more than that I can't think of :/ There might have been some inaccurate translation on my side, sorry about that. The question does not ask us for a define value of ##v_0##, rather an expression...

Hello Physicsforum! This is my attempt: First I realised: ##a_s=a_n## Secondly I used since previus known formulas: ##a_n=\frac {v^2} {R}## ##v=v_0+a_s*t## Although now I do not know how to continue, any suggestions would be appriciated! Thanks for your help on beforehand :smile:

Thanks a lot for your help! Here is my solution (still not in LaTeX!):

Hello Physicsforum! My solution (sorry for not writing it in LaTeX, I don't feel it's necessary since this try was more of a shot in the dark): The answear should be (5/6)*a Had no idea of how to go about solving this, so tried using the followin equaiton (I have no idea what W stands for...

Thanks for your help! As per request, here comes the new improved FBD's: And the following equations: 1. ##F_f-S=-ma\Rightarrow -S=-ma-F_f## 2. ##F-S-F_f=Ma\Rightarrow -S=Ma-F+F_f## This gives: ##-ma-F_f=Ma-F+F_f## ##-a(M+m)=-F+2F_f##, where ##F_f=mg\mu## ##a=\frac {F-2mg\mu} {M+m}## Thanks...

Question picture: My solution: Where: S is the lineforce Ff is the force as a result of friction a is the resulting acceleration F is the acting force The answear is supposed to be a=(F-2mg(mu))/(m+M) Any idea what i could have missed? Thanks for your help on beforehand!

Thanks for your help! Here is my new solution to the problem (with the correct answear!) Thanks for you help and time!

Hello PhysicsForums! Here is my attempt at a solution for the problem stated above: Where m1 and m2 are the masses Where Ff1 and Ff2 are friction for each mass Where a1 and a2 is the resulting acceleration Where S is the fore of the wire (threadforce) Where FN is the normal force The answear...

Hello! In the following image, is it true that S1 = mg/2. Thanks for answears!