Center of gravity of this body: y = (x^2)/a (rotated about the x-axis)

  • Thread starter Thread starter Heexit
  • Start date Start date
AI Thread Summary
The discussion revolves around calculating the center of gravity for a body defined by the equation y = (x^2)/a when rotated about the x-axis. The proposed solution suggests that the center of gravity is (5/6)*a, although the original poster expresses uncertainty about their approach. Suggestions for improvement include using the formula for the center of mass of a solid of revolution, specifically integrating the volume of disks. There is also a note regarding potential confusion in notation, particularly with the letter 'x' resembling the Greek letter alpha. The conversation emphasizes the importance of clarity in mathematical expressions and proper integration techniques.
Heexit
Messages
10
Reaction score
3
Homework Statement
A homogeneous body is formed by rotating the surfaces in the image around the x-axis (see picture). Determine the location of the center of gravity.
Relevant Equations
N/A
Hello Physicsforum!

1684871079539.png


My solution (sorry for not writing it in LaTeX, I don't feel it's necessary since this try was more of a shot in the dark):
1684870996184.png


The answear should be (5/6)*a

Had no idea of how to go about solving this, so tried using the followin equaiton (I have no idea what W stands for in this case, but it can be switched out for mass/volume/area):
1684871334533.png


Any suggestions about what could have gone wrong alternatively what I should do instead would be appreciated!

Thanks on beforehand:smile:
 
Physics news on Phys.org
W could means weight.
 
This is a solid of revolution. It looks like you need to use $$\bar X=\frac{\int x~ dV}{\int dV}$$where ##dV## is the volume of a disk of thickness ##dx## and radius ##y##.
 
kuruman said:
This is a solid of revolution. It looks like you need to use $$\bar X=\frac{\int x~ dV}{\int dV}$$where ##dV## is the volume of a disk of thickness ##dx## and radius ##y##.
Thanks a lot for your help!
Here is my solution (still not in LaTeX!):
1684875471699.png
 
Looks OK even though not in LaTeX. Your letter ex in places looks a bit like the Greek letter alpha and that could be confusing.
 
  • Like
Likes Heexit, berkeman and MatinSAR
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top