Recent content by homegrown898

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    Is the square of a function always positive

    I'm curious, is the square of any function always positive? It seems obvious that it's always positive because if you have a function (F), an input (x) and an output (y) then you have y = F(x) And if you square the function then (F(x))2 = y2 which means that every value in the range is...
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    Sums of 6th and 7th degree powers

    I understand the approach you are taking, but I don't understand how setting y as a constant allows us to show that there is no solution to (x+y)6 = x6 + y6 other than x=0 or y=0 for all possible values of x and y
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    Sums of 6th and 7th degree powers

    This is a very similar question to what I posted earlier. Basically I am trying to find when (x+y)6 = x6 + y6 assuming that xy≠0 I am trying to play with it algebraically to find a contradiction, but have been unsuccessful I'm also working on (x+y)7 = x7 + y7 assuming xy≠0 I'm...
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    Interchanging mathematical operations proof

    I haven't tried that no and I'm not exactly sure what you mean
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    Interchanging mathematical operations proof

    I'm working on the following two proofs: 1.) (x+y)2n+1 = x2n+1 + y2n+1 if and only if x=0, y=0 or y=-x and 2.) (x+y)2n = x2n + y2n if and only if x=0 or y=0 I've tried using induction and get stuck at a certain point. I've also tried playing around with...
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    Inequality proof involving Infs and Sups

    Homework Statement Let F and G be bounded functions on S. If f(x) <= g(x) for all x in S prove that inf{f(x):x belongs to S} <= inf{g(x):x belongs to S} Homework Equations None The Attempt at a Solution Basically the idea is to let L0 = inf{f(x):x belongs to S} and L1 = inf{g(x):x...
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    Two Variable Equation Word Problem

    A club consisting of seniors and juniors has 15 members. After seven more seniors and three more juniors join the club, the ratio of juniors to seniors is 2:3. How many juniors are in the club? I guess the thing that screws me up is the ratio part. I don't know what to do. I've found a...
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    How to Solve Fractional Equations with Squared Variables?

    I don't want to learn Latex right now because it will take too long but I'll learn it for the future. This is what I'm getting: xsquared - 2x - x = xsquared + x - 6 I subtract xsquared on each side to cancel them out getting: -2x - x = x - 6 I then subract x from each side getting...
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    How to Solve Fractional Equations with Squared Variables?

    Moo, that was right what you posted And that is where I got but the instructions are to solve Is that a solution to it?
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    How to Solve Fractional Equations with Squared Variables?

    Because I can't write squared, if x is squared, I will just write it like this: xsquared x/x +2 MINUS x/xsquared - 4 = x+3/x+2 I get an LCD for each fracton and then I subtract getting this: xsquared - 2x MINUS x/xsquared - 4 = (x+3)(x-2)/xsquared - 4 What do I do now? If you...
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    Solving Ratio Word Problem: ~36 Brand Y Refrigerators

    I would say that for every 4 brand X refigerators, there are 11 Brand Y refigerators sold.
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    Solving Ratio Word Problem: ~36 Brand Y Refrigerators

    That in 100 refigerators are sold between the two? Or with the problem you gave me I cross multiplied which gave me 4y = 11x I'm not so sure. :frown:
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    Solving Ratio Word Problem: ~36 Brand Y Refrigerators

    That for every 4 of the X Brand, there are 11 of the Y Brand sold?
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    Solving Ratio Word Problem: ~36 Brand Y Refrigerators

    An appliance store sells only two brands of refigerator. The ratio of the number of brand X refigerators sold at this store to the number of Brand Y refigerators sold is about 4 to 11. Of the next 100 refigerators the store sells, approximately how many will be brand Y? I don't know how to...
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    Solve Algebra Word Problem: x+1/x - 1/4 = x+3/x+2

    http://www26.brinkster.com/nick898/question.htm I`ve scanned the question so you can understand it better. This is how I started... x+1/x - 1/4 = x+3/x+2 But this is how far I got. I don`t know what do after this part and I don`t even know if what I`m doing is correct.
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