Wow! I'm sorry, that was definitely one of my stupid things. Thanks for pointing that out! The container is filled with a monatomic gas. So I should be using C_p for that.
So, since C_p = R + C_v and C_v = 3/2 * R ( for a monatomic gas) then C_p = 5/2 * R
So that would give ( with the R's...
Homework Statement
A container has a 100 cm^2 piston with a mass of 10 kg that can slide up and down vertically without friction and is placed below a heater.
Suppose the heater has 25 W of power and are turned on for 15 s. What is the final volume of the container?
Initial Volume: 800 cm^{3}...
Your problem is not in calculating the mass of O2, rather your problem is that it's O2 and not O.
The equipartition theorem states that a system has an average energy of kT/2 in each quadratic degree of freedom (mode in which the gas can store the energy). A monatomic gas can store energy as...
Homework Statement
At 100 Celcius the rms speed of nitrogen molecules is 576 m/s. Nitrogen at 100 Celcius and a pressure of 2.0 atm is held in a container with a 10cm x 10cm square wall.
Homework Equations
rate of collisions: N_coll/ \Deltat = (N*A*v_x)/(2V) (this is from my textbook)
ideal...
Although, it retrospect this can't be right since
deltaL = ( (3 * 10^4 * 9.8) / .00576 * .8) / (.00144 * 10^10) meters
= 2.84 m
and that is way to large to be realistic
Hang on, I see the mistake I made earlier: 3.8 cm x 3.8 cm = .038m x .038m = .00144 m^2 (thanks btw), but wouldn't then total area then be 4 * .00144 = .00576 m^2 ?
Then the pressure would be 3 * 10^4 * 9.8 / .00576.
Then plug in that pressure for F in
deltaL = F*L_0/(Y*A)
Is that right?
4*.144 = .576 m^2
but, isn't it asking the deltaL for an individual post?
I thought that I might have to divide the force by 4, but that answer was also incorrect.
Thanks
So I took the mass of water to be 1Kg per liter.
So the m = 3 * 10^4
Then the equation comes out as:
deltaL = ( 3 * 10^4 * 9.8 * .8)/(.144 * 10^10) meters
= 1.63 * 10^-4 m
But I am told this is the incorrect answer.
Any help?
Thanks!
Homework Statement
A large 3.00×10^4 L aquarium is supported by four wood posts (Douglas fir) at the corners. Each post has a square 3.80 cm x 3.80 cm cross section and is 80.0 cm tall.
By how much is each post compressed by the weight of the aquarium?
Homework Equations
deltaL =...
Hello, I am attaching what was an extra credit question in my physics class which I didn't understand at all. The topic isn't in the book and all the internet searchs I read confuse me. I was hoping someone might give me a walk through.
Thanks!
image
It's been pending approval for longer than my patience. I got imageshack to host.
URL: http://img88.imageshack.us/my.php?image=prb1gr7.jpg
Thanks