Recent content by howie8594

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    Moment of Inertia of Hollow Sphere about Center Axis x-y-z method

    Oh ok that makes sense. I got the right answer doing it that way. Now I see why everyone uses the angle method instead. Thanks ehild.
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    Moment of Inertia of Hollow Sphere about Center Axis x-y-z method

    Homework Statement Find the moment of inertia of a hollow sphere about a vertical axis through its center in terms of its mass M and radius R. Homework Equations I=\int r^{2} dm The Attempt at a Solution I've been curious about different methods for finding moments of inertia...
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    What force is needed to produce a constant speed?

    The density of water is not 1 g/mm^3
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    Physics 12 energy/work question

    If you use "Fd" on the left side of your equation, then instead of msin30(12), it should be mgsin30(12), since mgsin30 is the force pulling the box down the slope. There's a slightly easier way to do this. Since the incline is 30 degrees, then you know the height of the box has to be half of...
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    Optics Problem: A real object and a converging lens

    I believe your answer is correct. Remember that image height is proportional to the image distance. The greater the distance, the greater the height (it will be upside down though if its real). Therefore, the image will be magnified larger if the image distance is greater than the object distance.
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    Masses connected by a pulley on a frictionless surface

    I'm not sure how to draw on here, but I'll try to explain it to you the best way I can. If you draw out what's happening here, it's easier to understand. You have two masses connected by a string. One of those is hanging off the edge and one is sitting on a table, or whatever it's sitting...
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    Masses connected by a pulley on a frictionless surface

    I'm not sure what you mean by "only the mass of the two objects" but it's just Newton's second law. You need to add up the masses when solving for the acceleration.
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    Masses connected by a pulley on a frictionless surface

    That's exactly right. So what's the problem?
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    Baseball and medicine ball thrown with different KE/P/V

    I recommend plugging in some numbers to both formulas, say... .5 kg for the baseball and 5 kg for the medicine ball. Then make up a velocity for the baseball to be going. Solve for momentum and kinetic energy. Once you get momentum in kgm/s and kinetic energy in joules, then plug those in for...
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    Baseball and medicine ball thrown with different KE/P/V

    Think about that answer. If you catch something 10 times heavier going at the same speed, it's kinetic energy and its momentum are both going to be multiplied by 10. So given that you have a choice between the same momentum, the same kinetic energy, or 10 times as much momentum and kinetic...
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    Masses connected by a pulley on a frictionless surface

    You still need to factor in the mass of the block off the table. Remember, you're trying to find the acceleration of the system.
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    Grade 11 Physics, Need resources

    I'm sure there are hundreds of articles online that can help you with this. Just google vectors. If you have any specific homework problems you're having trouble with, feel free to post those.
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    Help With Understanding why weight in the x direction is MG*SIN*Theta

    Yes, except the theta should be in between mg and mgcos(theta).
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    Grade 11 Physics, Need resources

    You're going to need to be a lot more specific than that. What physics concepts are you learning?
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