now this makes total sense. Since I have no length in either frame I cannot use the Length contraction equation. The 10 years I plugged into the length contraction equation is not a length but a time...
Thank you for helping me with this Vela. I greatly appreciate it...
If I use d=vt I get:
d=0.80c(10years) = 8 Lightyears for the people on earth
d=0.80(6years) = 4.8 Lightyears for the astronauts
I was under the impression that d=vt was not valid for speeds close to the speed of light?
(I'm a little confused was finding the distance via the...
You have a Square with 10cm lengths on each side. Charges of +4 microC (top right corner), -6 microC (top left corner), and +4 microC (bottom left corner) are located at three corners of the square.
A) Calculate the electric field in the empty corner of the square.
The only formula I thought fit after doing multiple relativity questions was Length contraction for a question like this. Is there another way to solve it?
I tried time dilation first thinking time/years seems reasonable, but my answers were wacky. But it may have been a mathematical error...
Initially unpolarized light with an intensity of 240W/m2 is incident on a series of two polarizers. What should be the angle between to the axes of the two polarizers such that the transmitted intensity after the second polarizer is 37.5% of the incident one?
Distance on earth inertial frame = 0.80c(10years) = 8yc (does yc = light years?)
Distance on spaceships inertial frame 0.80c(6years) = 4.8yc
Thanks... does all the other stuff look correct?
Thanks for your help
A) at what velocity will be the KE of a spaceship 2/3 of its rest energy?
B) If the Spaceship travels at this velocity relative to the earth and its trip takes 10 years as measured in the earthbound system, how much time has elapsed on the spaceship clock?
C) What is the...
Light of wavelength 680 nm falls on two slits and produces an interference pattern in which thefourth-order fringe is 38 mm from the central fringe on a screen 2.0 m away. What is the separationof the two slits?
The object distance is defined as the distance between the object and the lens.
for the first lens i got an image distance of 125cm. This goes beyond the second lens so to consider the first image as the second object wouldn't i have to subtract the distance in between the two lens and the...
Two 28.0-cm-focal-length converging lenses are placed 16.5 cm apart. An object is placed 36.0 cm in front of one lens. Where will the final image be formed by the second lens?
1/do + 1/di = 1/f
The Attempt at a Solution
for the first...