Recent content by Juan Carlos

Hello, First of all, it would be nice to see explicitly your attempt of the solution. However, I don't think that you should use the power series method to solve the Radial Schroedinger equation at ##r<a##. In this approach, the problem arises once you impose boundary conditions. NOTE: I will...

Hello Ted. Looking through your expressions, I guess that you are using the same notation of the book ("Principles of Statistical Mechanics" by Amnon Katz). Two points: What is the expression of your statistical functions ##f##'s? I assume that it should be something like this for system...

Thanks I will try with this "factorization" procedure.

Variation of parameters! I'll give it a try! Thanks

Hello! Im trying to solve this second order differential equation: \begin{equation*} -\dfrac{d^2y}{dx^2}+\dfrac{3}{x}\dfrac{dy}{dx}+(x^2+gx^4+2)y=0 \end{equation*} Any idea? Maybe it could be converted to a Bessel-like equation (?) with an appropriate change of variables. The equation...

for sure, there is a total derivated connecting both.

and the reason is? I repeat, equations of motion don't change.

I get your point, is the usual treatment for one particle. But what I'm saying is related to the two particle system, where the question is: Is it correct use two different gauges, one for each particle? Thank you

For Example: Let's suppose we have the magnetic field in the z direction, for example two Landau's gauges: \vec{A_{1}}=B(-y,0,0) and \vec{A_{2}}=B(0,x,0) where both satisfy \vec{B}=B\vec{k} . So in particular I could say that my Hamiltonian for the two particle system is...

It's the standard construction. It's the standard construction.

It's well known when if we are working on problems related to particles in presence of an electromanetic field, the way we state the problem can be done using the next Hamiltonian: H=\dfrac{(p-\frac{e}{c}A)^2}{2m} +e \phi where the only condition for A is: \vec{\nabla } \times \vec{A} =\vec{B}...

It's well known when if we are working on problems related to particles in presence of an electromanetic field, the way we state the problem can be done using the next Hamiltonian: H=\dfrac{(p-\frac{e}{c}A)^2}{2m} +e \phi where the only condition for A is: \vec{\nabla } \times \vec{A} =\vec{B}...

Hi! I'm having problems with this simple problem: Consider two level system: a box containing one particle, the box is divided by a thin membrane. Let Ψ1 and Ψ2 the probability amplitude (time-dependent only) of being on the left and right side. The particle can tunnel through the partition: so...

Hi! I'm having problems with this simple problem: Consider two level system: a box divided by a thin membrane. Let

I agree. And I used those properties. Thanks