Recent content by kieth89

  1. K

    Intersection Line for Two Planes

    Yay! So it is due to different starting points. Thanks for the help everyone.
  2. K

    Intersection Line for Two Planes

    Homework Statement Find an equation of the line where the planes Q and R intersect. Q: -2x + 3y - z = 1; R: x + y + z = 0 Homework Equations Equation of a Plane: ax + by + cz = d, where \vec{n} = <a, b, c> Equation of a Line in R^{3}: \vec{r}(t)=<x_{0}, y_{0}, z_{0}> + t<x,y,z> The Attempt at...
  3. K

    Varying Forms for an Equation of a Line in R^3

    Oh, that makes perfect sense. Thank you!
  4. K

    Varying Forms for an Equation of a Line in R^3

    I was doing some course work earlier today and noticed that I've seen two different equations for a line in 3D space. Usually the equation I use is: \vec r(t)=<x_{0}, y_{0}, z_{0}> + t<x, y, z> You plug in the various points with what the problem provides. However, a few times I have seen a...
  5. K

    Spring Constant to Bring a Car to Rest

    Oh. So the deceleration cannot be constant if it is only a spring causing it then due to the increasing force as it compresses more? Is that why the basic kinetic equations fail here, because they're finding a constant acceleration?
  6. K

    Spring Constant to Bring a Car to Rest

    Since the car travels 8 meters to stop given a constant deceleration of 5g wouldn't the max compression be 8m? Which would make the F=17150*8, a very large number.. But we took time into account when we found the x distance, so I'm not understanding why the k constant is so large. It feels...
  7. K

    Spring Constant to Bring a Car to Rest

    Homework Statement What should be the spring constant k of a spring designed to bring a 1400 kg car to rest from a speed of 28 m/sec so that the occupants undergo a maximum acceleration of 5g’s? I have the solution manual and can see how they did this, but am curious as to why my attempt did...
  8. K

    Derivatives and the relation to limits

    I'm in calc 1 and want to make sure I'm understanding the reason that we find derivatives. From what I understand, a derivative is simply an equation for the rate of change at any given point on the original function. Is that correct? And the tangent line at point (x,y) is obtained by using...
  9. K

    Prerequisites and Resources to learn Matrices

    I think I know where I need to go/what I need to look at next. Thank you all for the help!
  10. K

    Prerequisites and Resources to learn Matrices

    As far as matrix math goes I've done dot multiplication and other things among that level, but it's been about 6 months so I'm probably pretty rusty. As far as general math education, I'm pretty high college algebra level/right before calculus (have looked at calculus a little bit, but not much).
  11. K

    Prerequisites and Resources to learn Matrices

    Could anyone let me know of a good resource that I could use to learn matrix mathematics? I'm not sure if that is the proper term for that segment of mathematics, but hopefully you get the gist of it. It can be a book or a website, does not matter to me. Also, any suggestions as to what I...
  12. K

    I give up Basketball Projectile problem.

    Thanks for the help..I figured it out, but the program didn't like how I formatted my answer (gave it the range instead of the difference between the two extremes) so I still got it wrong :(...At least I know how to do it for the test now though.
  13. K

    I give up Basketball Projectile problem.

    Plugging the numbers into that formula results in taking the square root of a negative..and there should be no i in this Physics problem. With my values plugged in the equation looks like this (for the high end): v_{0} = \sqrt{6.22 tan(40°) - 9.8 x^{2} (\frac{1 + tan(40°)^{2}}{2*0.7}} Which...
  14. K

    I give up Basketball Projectile problem.

    Homework Statement A basketball leaves a player's hands at a height of 2.20 above the floor. The basket is 2.90 above the floor. The player likes to shoot the ball at a 40.0 degree angle. If the shot is made from a horizontal distance of 6.00 and must be accurate to plus or minus .22...
  15. K

    Very Stuck on Deriving Projectile Motion Formulas

    So you do use the v_{0}{x} = v_{0} cos \Theta? Which would change the answer to: Δx = \frac{2v_{0}^{2}cos\Theta sin\Theta}{g} Again, I used my answer for Part B as t here. Should I not be using v_{x0} and instead just using v_{x}. I wouldn't think it matters, because in this case the...
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