kieth89
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Homework Statement
What should be the spring constant k of a spring designed to bring a 1400 kg car to rest from a speed of 28 m/sec so that the occupants undergo a maximum acceleration of 5g’s?
I have the solution manual and can see how they did this, but am curious as to why my attempt did not work. It didn't seem to break any rules that I can see.
a = -5g = -49 {\frac{m}{s^{2}}} neg. due to deceleration
m = 1400 kg, v_{0} = 28 {\frac{m}{s}}, v = 0 {\frac{m}{s}}
Homework Equations
I went about the problem in a roundabout way. The equations used are:
v = v_{0} + at
x - x_{0} = v_{0}t + {\frac{1}{2}}at^{2}
KE = PE
{\frac{1}{2}}mv^{2} = {\frac{1}{2}}Kx^{2}
The Attempt at a Solution
v = v_{0} + at
0 = 28 + -49t
t =0.57143 s
x - x_{0} = v_{0}t + {\frac{1}{2}}at^{2}
x - 0 = (28)(0.57143) + {\frac{1}{2}}(-49)(0.57143)^{2}
x = 8
{\frac{1}{2}}(1400)(28)^{2} = {\frac{1}{2}}K(8)^{2}
K=17150 Nm
I believe the correct answer is 4288 Nm based on a similar problem in the solution manual. I don't understand why working it like this does not work though. All the units work out, and while I know that's not a guarantee of correct setup it is usually a sign you are moving in the right direction. Anything stand out in particular here?
Thanks!