Recent content by Kolika28

  1. K

    Diffusion or turbulence?

    Ohh, thank you! Really appreciate your help!
  2. K

    Diffusion or turbulence?

    It's called DIYnamics. Here is a link to a youtube video
  3. K

    Diffusion or turbulence?

    Thank you for a great answer! :smile:
  4. K

    Diffusion or turbulence?

    <Mentor moved to Physics> My teacher talks about turbulence (2D and 3D), but I don't quite understand this. How is the turbulence different in the two buckets, and why does my teacher talk about turbulence but not diffusion? Is not diffusion the reason why the dye spreads in the water? I have...
  5. K

    What does it mean that a rigid body is in equilibrium?

    Ohh, I see, that make sense. Thank you so much both of you! :smile:
  6. K

    What does it mean that a rigid body is in equilibrium?

    So I have always been thinking that equilibrium means that an object is not moving or having constant acceleration. On a webside they said: " A rigid body is in equilibrium when it is not undergoing a change in rotational or translational motion. " To me it sounds like the object then must not...
  7. K

    Buoyancy force when a ramp is under water

    Yeah, I see that now. Thank you both for the help by the way!
  8. K

    Buoyancy force when a ramp is under water

    Hmm, I see. But if I were to use the two equations, I would have to make sure that ##\sum F_y=mg*cos(15)+T_b sin(75)-mgcos(15)=0## ? And that would make the m=408.3 kg:oops:
  9. K

    Buoyancy force when a ramp is under water

    The buoyant force is ##F_b=\frac{1000}{2400}kg*g## The effective force is ##m=1kg-##mass of water##=(1-\frac{1000}{2400})kg## But what is the importance of the effective weight in this problem? Are these equations wrong by the way
  10. K

    Buoyancy force when a ramp is under water

    I have been looking at the units but I still don't see it :confused: ##2400 kg/m^3=\frac{1kg}{V_{block}}## ##V_{block}=\frac{1}{2400}m^3## ##p_{water}=1000 kg/m^3=\frac{mass}{\frac{1}{2400}m^3}## ##mass=p_{water}*V_{water}=1000kg/m^3* \frac{1}{2400}m^3= \frac{1000}{2400}kg##
  11. K

    Buoyancy force when a ramp is under water

    Yeah, I also think it was weird that they used the word weight, because I also thought kg/m^3 is density. So I just assumed the person who wrote the problem mixed up the words. But I struggle with finding the acceleration, do you know how?
  12. K

    Buoyancy force when a ramp is under water

    Hmm, I'm sorry, but I don't understand. Why does the water displaced have the mass of 1000 kg? I thought like this ##p_{concrete}=m_{block}/V_{block}## ##V_{block}=1/2400 m^3=V_{water}## ##p_{water}=m_{water}/V_{water}## ##m_{water}=1000/2400 kg##
  13. K

    Buoyancy force when a ramp is under water

    So I have made force diagram And I think that I should find the acceleration by using these equations: ##\sum Fx=w\sin(15)-f_k-T_{x-buoyancy} ## ##\sum F_y=N+T_{y-buouancy}-w ## I know that the volume of water displaced must be ##V=\frac{1}{2400}m^3## and the mass of the water is then...
  14. K

    Help with understanding this rigid-body equilibrium problem

    Thank you so much everybody for your relplies, I really appreciate it!:smile: I will now try to solve some more problems like this with your comments in mind, and see if I understand it better now.
  15. K

    Help with understanding this rigid-body equilibrium problem

    So here are two problems I have been working with lately: I have solved both, so I don't need the help to find the answers. The thing that confusses me is which object one should choose to apply the equations above. When it comes to the first problem, we apply the equations to the pole, but...
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