Recent content by laser123

Homework Statement Compute the change in internal energy, ΔU, and the final temperature, Tf, when 1 mole of an ideal, diatomic gas is compressed adiabatically to 89.700% of its initial volume. The starting point is 22.500°C and 16.100 L. (Assume that the vibrational degree of freedom stays...

Thanks Jorriss, I think that's why the physics majors have a little easier time than the chemistry majors. At least at my school we only take through calc 2. Dr. Du I appreciate it!

I just got out of the first p-chem. So no syllabus for like 5 weeks.

No sir.

Hey guys, I hope this is the right spot to this. I don't want to get another infraction. I just got recently got out of my first physical chemistry class and am now thinking towards the second one. I'm wondering which book would be the best supplement to read over the break and help me get...

And my solubility test said it was a low MW and neutral too...

Thanks guys, the boiling point was 155°C-165°C which has given me a choice of 6 possible compounds. List compound with respective boiling point in (°C): (+-)-4-Heptanol 156, 1-hexanol 159, cyclohexanol 160, (+-)-2-Heptanol 160, 3-chloro-1-propanol 161, (+-)-cis-2-methylcyclohexanol 165...

Hey Borek, thanks for helping. I turned my preliminary in and was right. So it is either a (low MW neutral alkene, alkyne, alchohol, ketone, amide, nitro compound, aldehyde, ester, ether). I have another question though, my professor told me to proof check my boiling point and put a no by it...

Oooops you're right.lol. That's what i meant. I read the scale at 0.036g. And then at 0.041g. It felt like I hardly put anything in there.

Thanks. I was just worried and freaking out that I did something wrong.

1. Homework Statement Okay, I just started working on my unknown in Lab and I got stuck with a liquid. First I determined the boiling point, my professor told me to let this step go for 30 minutes and it plateaued at around 147°C. I did this twice the first time I didn't do it as long and got...

For momentum i set up <P>=∫((√30/L^5)) P((√30/L^5)x(L-x))/1[/STRIKE] because the function is already normalized. So i subbed -iℏd/dx for p and distributed and applied the derivative function. Then I took the actual integral from 0 to L of what was left over. it all canceled very nicely, but...

I calculated the expectation value of the momentum to be <p> to be 0. The kinetic energy i calculated this to be (5/L^3)(ħ^2/2m). I have no idea how to do the last part! A dummy walk through on this uncertainty principle part would be awesome :D. Thank you! Thanks jmcleve

I am familiar with the momentum operator. Not so much with the kinetic energy or position operator Thank You!

[b]1. consider this wave function ψ(x)=(√(30/L^5))(L-x) if 0≤x≤L and 0 else [b]2. Compute the expectation value of the momentum. Compute the expectation value of the kinetic energy. Compute Δ p⋅Δ x...